Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Engine Efficiency The efficiency of an internal combustion engine is Efficiency \((\%)=100\left[1-\frac{1}{\left(v_{1} / v_{2}\right)^{c}}\right]\) where \(v_{1} / v_{2}\) is the ratio of the uncompressed gas to the compressed gas and \(c\) is a positive constant dependent on the engine design. Find the limit of the efficiency as the compression ratio approaches infinity.

Short Answer

Expert verified
The limit of the engine's efficiency as the compression ratio approaches infinity is 100%.

Step by step solution

01

Establish the limit

First, let's set up the limit to be solved. Here, the limit of the engine's efficiency is in question as \(v_{1} / v_{2}\) approaches infinity. So, write it like this: \( \lim_{{v_{1} / v_{2} \to \infty}} 100\left[1-\frac{1}{\left(v_{1} / v_{2}\right)^{c}}\right] \)
02

Simplify the Expression

Now, the next step is to simplify the expression inside the bracket of the efficiency formula. Divide \(v_{1}\) and \(v_{2}\) by the highest power of \(v_{1}/v_{2}\), which is \(\left(v_{1} / v_{2}\right)^{c}\) in this case. So, when you perform the long division, \(v_{1} / v_{2}\) divided by \(\left(v_{1} / v_{2}\right)^{c}\) will be \(1/\left(v_{1} / v_{2}\right)^{c-1}\) which is \(0\) as \(v_{1} / v_{2}\) approaches infinity.
03

Calculate the Limit

Replace the expression inside the bracket with the value you obtained in the previous step which is \(0\). So, the expression becomes \( \lim_{{v_{1} / v_{2} \to \infty}} 100\left[1-0\right] \)
04

Finalize the Solution

Perform the operation inside the bracket which gets \(1\). Multiply it by 100 to get the final answer. So, \( \lim_{{v_{1} / v_{2} \to \infty}} 100 X 1 =100.\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Exercises \(75-86\), use a computer algebra system to analyze the graph of the function. Label any extrema and/or asymptotes that exist. $$ f(x)=\frac{2 \sin 2 x}{x} $$

Use a graphing utility to graph \(y=x \sin (1 / x)\). Show that the graph is concave downward to the right of \(x=1 / \pi\).

The function \(s(t)\) describes the motion of a particle moving along a line. For each function, (a) find the velocity function of the particle at any time \(t \geq 0\), (b) identify the time interval(s) when the particle is moving in a positive direction, (c) identify the time interval(s) when the particle is moving in a negative direction, and (d) identify the time(s) when the particle changes its direction. $$ s(t)=t^{3}-20 t^{2}+128 t-280 $$

In Exercises \(57-74\), sketch the graph of the equation. Look for extrema, intercepts, symmetry, and asymptotes as necessary. Use a graphing utility to verify your result. $$ y=\frac{2 x^{2}}{x^{2}+4} $$

Consider a fuel distribution center located at the origin of the rectangular coordinate system (units in miles; see figures). The center supplies three factories with coordinates \((4,1),(5,6),\) and \((10,3) .\) A trunk line will run from the distribution center along the line \(y=m x,\) and feeder lines will run to the three factories. The objective is to find \(m\) such that the lengths of the feeder lines are minimized. Minimize the sum of the squares of the lengths of vertical feeder lines given by \(S_{1}=(4 m-1)^{2}+(5 m-6)^{2}+(10 m-3)^{2}\) Find the equation for the trunk line by this method and then determine the sum of the lengths of the feeder lines.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free