Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Average Cost A business has a cost of \(C=0.5 x+500\) for producing \(x\) units. The average cost per unit is \(\bar{C}=\frac{C}{x},\) Find the limit of \(\bar{C}\) as \(x\) approaches infinity.

Short Answer

Expert verified
The limit of \(\bar{C}\) as \(x\) approaches infinity is 0.5

Step by step solution

01

Substitute \(C\) in terms of \(x\) into \(\bar{C}\)

In order to find the limit, the first step involves substituting the cost function in terms of \(x\) into the average cost function. Hence, \(\bar{C}=\frac{0.5x + 500}{x}\).
02

Simplify the fraction

The fraction \(\frac{0.5x + 500}{x}\) can be split into two different fractions as \(\frac{0.5x}{x} + \frac{500}{x}\). This simplifies to \(0.5 + \frac{500}{x}\).
03

Find the limit as \(x\) approaches infinity

By the properties of limits, when applying the limit as \(x\) approaches infinity to each term separately, we get \(\lim_{x \to \infty}(0.5) + \lim_{x \to \infty}(\frac{500}{x})\). The first term is simply \(0.5\) since there is no \(x\) present, and the second term goes to \(0\) as any constant divided by infinity results in zero.
04

Compute the final result

From the above calculation, the limit of \(\bar{C}\) as \(x\) approaches infinity is \(0.5 + 0 = 0.5\). So the average cost per unit approaches $0.5 as the number of units produced increases indefinitely.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free