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Identify the open intervals on which the function is increasing or decreasing. $$ h(x)=\cos \frac{x}{2}, 0

Short Answer

Expert verified
The function is decreasing on the open interval (0, \(2 \pi\)).

Step by step solution

01

Find the derivative

The derivative of h(x) using the chain rule is \(h'(x) = -\frac{1}{2} \sin \frac{x}{2}\).
02

Find critical points

To find the critical points, set \(h'(x)\) equal to zero, \(-\frac{1}{2} \sin \frac{x}{2} = 0\). Solving this gives \(x = 0\) and \(x = 2 \pi\). However those are the end points and not included in the interval.
03

Test intervals

Plug a number between 0 and 2 \(\pi\) into \(h'(x)\) to see if you get a positive or negative number. It's simple to check this with adding the sine function, where we know that \(x = \pi\) is a decreasing function. Therefore, the entire interval from (0, \(2 \pi\)) is decreasing.

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