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In Exercises \(7-14,\) find the differential \(d y\) of the given function. $$ y=3 x^{2}-4 $$

Short Answer

Expert verified
The differential \(dy\) of the function \(y=3x^2-4\) is \(dy = 6x \cdot dx\).

Step by step solution

01

Write the function

The given function is \(y=3x^2-4\).
02

Differentiate the function

Taking the derivative of the function with respect to \(x\), yield \(dy/dx = 6x\). This was achieved by applying power rule which suggests that the derivative of \(x^n\) is \(nx^{nāˆ’1}\). Here \(n=2\) for \(3x^2\), thus the derivative is \(2*3x^{2-1} = 6x\). The constant term \(-4\) disappears during differentiation.
03

Write the differential

The differential of a function is given by \(dy = f'(x) dx\). As we've differentiated y earlier and found its derivative \(dy/dx=6x\), the expression for differential \(dy\) becomes \(dy = 6x \cdot dx\).

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