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True or False? Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. If \(x=c\) is a critical number of the function \(f,\) then it is also a critical number of the function \(g(x)=f(x)+k,\) where \(k\) is a constant

Short Answer

Expert verified
The statement is True. Any critical number for \(f(x)\) will remain a critical number for \(g(x) = f(x) + k\) where \(k\) is a constant, regardless of the value of \(k\).

Step by step solution

01

Understand the problem

The function \(g(x) = f(x) + k\) is basically the function \(f(x)\) shifted vertically by the constant \(k\). A critical number of a function is a number at which the derivative of the function is either zero or does not exist. Here, we need to determine whether a critical number \(x = c\) of \(f(x)\) will remain a critical number for the function \(g(x)\).
02

Analyze the derivative of the function \(g(x)

Considering the function \(g(x) = f(x) + k\), find the derivative \(g'(x)\). The derivative of \(g(x)\) would be \(g'(x) = f'(x) + 0\) (since the derivative of a constant is zero). This implies that the derivative of \(g(x)\) is the same as the derivative of \(f(x)\), regardless of the value of \(k\).
03

Connect the analysis to the problem

Since \(x = c\) is a critical number of \(f(x)\), then by definition, \(f'(c) = 0\) or does not exist. Thus considering our result in Step 2, \(g'(c)\) would also be 0 or undefined. This means that \(x = c\) is also a critical point of \(g(x)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Critical Points Definition
Critical points of a function are pivotal in the study of calculus, dictating where a function's derivative is zero or does not exist. Imagine you're climbing a mountain; critical points symbolize spots where you stop ascending or descending — the peaks, valleys, or plateaus. Mathematically, for a function f(x), a critical point occurs at x = c if the derivative f'(x) is zero (f'(c) = 0) or undefined. Critical points are essential as they help identify extremum points (maximums and minimums) and inflection points, where the function changes curvature.

To find these critical points, one must first calculate the derivative of the function and examine where it equals zero or is not defined. It's a bit like looking at a speedometer; when the speed drops to zero or the speedometer breaks, you've hit a critical point in your journey – that's what we look for in the graph of a function. Understanding critical points is crucial since they offer valuable insights into a function's behavior and help in solving optimization problems in various fields like economics, engineering, and beyond.
Derivative of a Function
The derivative of a function is a fundamental concept, akin to the instant snapshot of something in motion. Imagine a function as a smooth path and its derivative as the function's speed at any point along that path. For a function f(x), its derivative f'(x) signifies the rate at which f(x) is changing at a particular point. If you were driving, the derivative would be your speedometer reading at any given moment.

To compute the derivative, we employ calculus tools such as the power rule, product rule, quotient rule, and chain rule. These tools help us to differentiate functions and uncover the precise spots, the critical points, where the function's rate of change is nil or instantaneous changes are not definable. It's like discovering at what points along your path you halt or the path becomes infinitely steep. Therefore, understanding how to derive a function is essential for analyzing the function's growth rate, finding tangents to curves, and many more applications in both theoretical and practical problems.
Vertical Shifts in Functions
Vertical shifts are one of the simplest transformations we can apply to functions. They occur when we add or subtract a constant value k to the function f(x), resulting in a new function g(x) = f(x) + k. Visualize it as lifting or pushing down the entire graph of f(x) without altering its shape. It's like moving a picture up or down on a wall – the picture stays the same, but its position changes.

Importantly, vertical shifts do not affect the function's derivative other than translating it up or down along the y-axis. Therefore, if x = c is a critical point of f(x), then it will also be a critical point of the shifted function g(x), since the derivative at that point remains unchanged apart from the shift. In practice, this transformation is used to adjust models to fit data without changing the model's intrinsic properties, much like tweaking the elevation of a slide in a playground while keeping its shape intact for the same sliding experience.

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Most popular questions from this chapter

Consider the functions \(f(x)=\frac{1}{2} x^{2}\) and \(g(x)=\frac{1}{16} x^{4}-\frac{1}{2} x^{2}\) on the domain [0,4] . (a) Use a graphing utility to graph the functions on the specified domain. (b) Write the vertical distance \(d\) between the functions as a function of \(x\) and use calculus to find the value of \(x\) for which \(d\) is maximum. (c) Find the equations of the tangent lines to the graphs of \(f\) and \(g\) at the critical number found in part (b). Graph the tangent lines. What is the relationship between the lines? (d) Make a conjecture about the relationship between tangent lines to the graphs of two functions at the value of \(x\) at which the vertical distance between the functions is greatest, and prove your conjecture.

In Exercises \(57-74\), sketch the graph of the equation. Look for extrema, intercepts, symmetry, and asymptotes as necessary. Use a graphing utility to verify your result. $$ x y^{2}=4 $$

(a) Let \(f(x)=x^{2}\) and \(g(x)=-x^{3}+x^{2}+3 x+2 .\) Then \(f(-1)=g(-1)\) and \(f(2)=g(2) .\) Show that there is at least one value \(c\) in the interval (-1,2) where the tangent line to \(f\) at \((c, f(c))\) is parallel to the tangent line to \(g\) at \((c, g(c)) .\) Identify \(c .\) (b) Let \(f\) and \(g\) be differentiable functions on \([a, b]\) where \(f(a)=g(a)\) and \(f(b)=g(b) .\) Show that there is at least one value \(c\) in the interval \((a, b)\) where the tangent line to \(f\) at \((c, f(c))\) is parallel to the tangent line to \(g\) at \((c, g(c))\).

Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. An \(n\) th-degree polynomial has at most \((n-1)\) critical numbers.

Sketch the graph of \(f(x)=2-2 \sin x\) on the interval \([0, \pi / 2]\) (a) Find the distance from the origin to the \(y\) -intercept and the distance from the origin to the \(x\) -intercept. (b) Write the distance \(d\) from the origin to a point on the graph of \(f\) as a function of \(x\). Use a graphing utility to graph \(d\) and find the minimum distance. (c) Use calculus and the zero or root feature of a graphing utility to find the value of \(x\) that minimizes the function \(d\) on the interval \([0, \pi / 2]\). What is the minimum distance? (Submitted by Tim Chapell, Penn Valley Community College, Kansas City, MO.)

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