Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The volume of a cube with sides of length \(s\) is given by \(V=s^{3} .\) Find the rate of change of the volume with respect to \(s\) when \(s=4\) centimeters.

Short Answer

Expert verified
The rate of change of the volume with respect to the length of the side of the cube when \(s=4\) centimeters is 48 cubic centimeters per centimeter.

Step by step solution

01

Express the Problem Mathematically

The volume \(V\) of a cube with side length \(s\) is given by the formula \(V=s^{3} .\) The rate of change of the volume with respect to \(s\) is given by the derivative \(\frac{dV}{ds}\). To find this derivative when \(s=4\), we will plug \(s=4\) into the derivative equation after finding it.
02

Differentiate the Volume Equation

Taking the derivative of both sides of the volume equation with respect to \(s\), we obtain: \(\frac{dV}{ds} = 3s^{2}\).
03

Substitute the Given Value of \(s\)

Substitution \(s=4\), from the given problem, into the derivative equation results in: \(\frac{dV}{ds} = 3(4)^{2} = 48\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Exercises \(75-80\), evaluate the derivative of the function at the indicated point. Use a graphing utility to verify your result. \(\frac{\text { Function }}{y=\frac{1}{x}+\sqrt{\cos x}} \quad \frac{\text { Point }}{\left(\frac{\pi}{2}, \frac{2}{\pi}\right)}\)

The displacement from equilibrium of an object in harmonic motion on the end of a spring is \(y=\frac{1}{3} \cos 12 t-\frac{1}{4} \sin 12 t\) where \(y\) is measured in feet and \(t\) is the time in seconds. Determine the position and velocity of the object when \(t=\pi / 8\).

If the annual rate of inflation averages \(5 \%\) over the next 10 years, the approximate cost \(C\) of goods or services during any year in that decade is \(C(t)=P(1.05)^{t},\) where \(t\) is the time in years and \(P\) is the present cost. (a) If the price of an oil change for your car is presently \(\$ 24.95,\) estimate the price 10 years from now. (b) Find the rate of change of \(C\) with respect to \(t\) when \(t=1\) and \(t=8\) (c) Verify that the rate of change of \(C\) is proportional to \(C\). What is the constant of proportionality?

In Exercises 35 and 36, find an equation of the tangent line to the graph of the equation at the given point. $$ \arctan (x+y)=y^{2}+\frac{\pi}{4}, \quad(1,0) $$

Adiabatic Expansion When a certain polyatomic gas undergoes adiabatic expansion, its pressure \(p\) and volume \(V\) satisfy the equation \(p V^{1.3}=k\), where \(k\) is a constant. Find the relationship between the related rates \(d p / d t\) and \(d V / d t\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free