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Find the derivative of the function. \(y=x^{2} e^{-x}\)

Short Answer

Expert verified
The derivative of the function \(y=x^{2} e^{-x}\) is \(y' = x e^{-x} (2 - x)\).

Step by step solution

01

Identify the Functions to be Differentiated

The first function \(f(x) = x^{2}\) and the second function \(g(x) = e^{-x}\). Now, the next task is to find out their derivatives.
02

Find the Derivatives of the Individual Functions

The derivative of \(f(x) = x^{2}\) is \(f'(x) = 2x\). The function \(g(x) = e^{-x}\) requires the chain rule for differentiation, the outer function is \(e^{x}\) while the inner function is \(-x\). Applying the chain rule, we get \(g'(x) = - e^{-x}\).
03

Apply the Product Rule

The product rule of differentiation states that the derivative of the product of two functions is the first function times the derivative of the second function plus the second function times the derivative of the first function. Substituting into the product rule, we get \(y' = f'(x)g(x) + f(x)g'(x) = 2x e^{-x} - x^{2} e^{-x}\).
04

Simplify the Result

We can factor out \(x e^{-x}\) to simplify: \(y' = x e^{-x} (2 - x)\).

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