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Sketch several representative vectors in the vector field. $$ \mathbf{F}(x, y)=x \mathbf{i}+y \mathbf{j} $$

Short Answer

Expert verified
The sketch of vectors in the vector field \( \mathbf{F}(x, y)=x \mathbf{i}+y \mathbf{j} \) gives insight into how a particle would move in this field. It's seen that the vectors point outward from the origin and their magnitude increases linearly as we move away from the origin. A particle would thus move in straight lines outward from the origin, accelerating as it moves further from origin.

Step by step solution

01

Understanding the Vector Field

The given vector field, \( \mathbf{F}(x, y)=x \mathbf{i}+y \mathbf{j} \), describes a vector's components along the x and y axis, respectively. A vector at a particular point (x, y) in the vector field can be represented by \( \mathbf{F}(x, y) \), which is simply the vector with x-components equal to x and y-components equal to y. Hence, it will be more of a linear field where the vectors increase in magnitude as we move away from the origin.
02

Begin Sketching the Vector Field

Start by sketching the vector at a few representative points. For example, let's pick the points (1, 0), (0, 1), (-1, 0), and (0, -1). At point (1, 0), the vector has its tail at the point (1,0) and points in the direction of the vector \( \mathbf{F}(1,0) = \mathbf{i} \), that is along the x-axis. Sketch this vector on the plane. Repeat this for the points (0, 1), (-1, 0), and (0, -1), sketching the respective vectors \( \mathbf{F}(0,1) = \mathbf{j} \), \( \mathbf{F}(-1,0) = -\mathbf{i} \), and \( \mathbf{F}(0,-1) = -\mathbf{j} \).
03

Continue Sketching More Vectors

Continue sketching vectors for more points in the plane. Try to include both positive and negative x and y coordinates, as well as points with x=y, to create a complete picture of the vector field. In the end, the pattern should be clear - the vectors point outward from the origin and their magnitude increase linearly as we move away from the origin in any direction. This visual representation gives a clear idea of how a particle would move in this vector field.

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