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Determine the value of \(b\) such that the volume of the ellipsoid \(x^{2}+\frac{y^{2}}{b^{2}}+\frac{z^{2}}{9}=1\) is \(16 \pi\)

Short Answer

Expert verified
The value of \(b\) such that the volume of the ellipsoid is \(16 \pi\) is \(b = 4\).

Step by step solution

01

Write down the volume formula for an Ellipsoid

The volume \(V\) of an ellipsoid with semi-axes \(a\), \(b\) and \(c\) is given by the formula:\(V = \frac{4}{3} \pi a b c\)
02

Substitute the known values into the volume formula

We know that \(a = 1\), \(b = b\) , \(c = 3\), and \(V = 16\pi\). Substituting these values into the volume formula gives:\(16\pi = \frac{4}{3} \pi \cdot 1 \cdot b \cdot 3\)
03

Simplify the resulting equation

Simplifying the equation results in:\(16 = 4b \)
04

Solve for \(b\)

To find \(b\), we will solve the equation from the previous step. Dividing both sides by 4, we get:\(b = 4 \)

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