Chapter 11: Problem 81
Hardy-Weinberg Law Common blood types are determined genetically by three alleles \(\mathrm{A}, \mathrm{B},\) and \(\mathrm{O} .\) (An allele is any of a group of possible mutational forms of a gene.) A person whose blood type is \(\mathrm{AA}, \mathrm{BB},\) or \(\mathrm{OO}\) is homozygous. A person whose blood type is \(\mathrm{AB}, \mathrm{AO},\) or \(\mathrm{BO}\) is heterozygous. The HardyWeinberg Law states that the proportion \(P\) of heterozygous individuals in any given population is \(P(p, q, r)=2 p q+2 p r+2 q r\) where \(p\) represents the percent of allele \(\mathrm{A}\) in the population, \(q\) represents the percent of allele \(\mathrm{B}\) in the population, and \(r\) represents the percent of allele \(\mathrm{O}\) in the population. Use the fact that \(p+q+r=1\) to show that the maximum proportion of heterozygous individuals in any population is \(\frac{2}{3}\)