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True or False? Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. The normal component of acceleration is a function of both speed and curvature.

Short Answer

Expert verified
The statement is True. The normal component of acceleration in curvilinear motion depends on both speed and curvature, as per the formula for normal or centripetal acceleration \(a_n = v^2 / r\).

Step by step solution

01

Break down the statement

First, understand the statement that needs to be evaluated: 'The normal component of acceleration is a function of both speed and curvature.' Here, it is proposed that the normal or centripetal acceleration depends on both speed and curvature of an object's path.
02

Consider the formula

Next, consider the formula used to calculate the normal or centripetal acceleration: \(a_n = v^2 / r\). In this formula, \(a_n\) is the normal component of acceleration, \(v\) is the speed, and \(r\) is the radius of curvature (reciprocal of curvature). Thus, it shows that the normal component of acceleration is indeed a function of speed (as \(v^2\)) and curvature (as \(1/r\)).
03

Make a decision based on the formula

Finally, as per the formula \(a_n = v^2 / r\), it is evident that the normal component of acceleration \(a_n\) depends on both speed \(v\) and curvature (\(1/r\)), which corroborates the given statement. Hence, the statement is True.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centripetal Acceleration
Centripetal acceleration plays a pivotal role in describing the motion of objects moving in a circular path. Imagine riding on a merry-go-round; the force that you feel pushing you towards the center of the ride is linked to centripetal acceleration. Centripetal acceleration is always directed towards the center of the circle and keeps the object on its circular path.

In physics, the formula for centripetal acceleration (\(a_c\text{ or }a_n\text{ for normal acceleration}\) is given by \( a_c = \frac{v^2}{r} \), where \( v \) is the speed of the object along the circular path and \( r \) is the radius of curvature of that path. This reveals the relationship between centripetal acceleration and the speed and curvature of the object's path. A higher speed or a tighter curve (smaller radius of curvature) results in greater centripetal acceleration. Understanding centripetal acceleration is essential not only in amusement park rides but also in designing curves on roadways, satellite orbits, and in many principles of rotational dynamics.
Curvature in Calculus
Curvature is a measure of how sharply a curve bends or how rapidly its direction changes. In calculus, it is quantified by the inverse of the radius (\( r \) of the 'osculating circle,' the circle that best fits the curve at a particular point. The smaller the radius of this osculating circle, the higher the curvature of the path at that point.

Mathematically, if a curve is represented by the function \( y = f(x) \) or parametrically as \( x(t), y(t) \) where \( t \) is a parameter, we can find an expression for the curvature (\( k \) using calculus. This involves derivatives and can be quite complex, but it is central to understanding how objects move along paths in real-world scenarios, such as the motion of planets in their orbits or the turning of a car on the road. The concept of curvature connects to the normal component of acceleration, hinting at the geometrical backing behind physical motion.
Speed in Physics
Speed is a scalar quantity that refers to how fast an object is moving. It is the rate at which an object covers distance. In physics, it is typically calculated as the distance travelled per unit of time, and is expressed in units like meters per second (m/s), kilometers per hour (km/h), or miles per hour (mph).

The instantaneous speed is the speed of an object at a particular moment in time, and in calculus, it can be found by taking the derivative of the position with respect to time. This concept of speed is crucial because it directly influences kinetic energy, momentum, and, as we saw with centripetal acceleration, the normal component of acceleration of an object. This relationship highlights the importance of speed in the analysis of motion, as it interplays with both force and energy to determine an object's motion along a specific path.

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Most popular questions from this chapter

Use the model for projectile motion, assuming there is no air resistance. A projectile is fired from ground level at an angle of \(12^{\circ}\) with the horizontal. The projectile is to have a range of 150 feet. Find the minimum initial velocity necessary.

Use the model for projectile motion, assuming there is no air resistance. Rogers Centre in Toronto, Ontario has a center field fence that is 10 feet high and 400 feet from home plate. A ball is hit 3 feet above the ground and leaves the bat at a speed of 100 miles per hour. (a) The ball leaves the bat at an angle of \(\theta=\theta_{0}\) with the horizontal. Write the vector-valued function for the path of the ball. (b) Use a graphing utility to graph the vector-valued function for \(\theta_{0}=10^{\circ}, \theta_{0}=15^{\circ}, \theta_{0}=20^{\circ},\) and \(\theta_{0}=25^{\circ} .\) Use the graphs to approximate the minimum angle required for the hit to be a home run. (c) Determine analytically the minimum angle required for the hit to be a home run.

The position vector \(r\) describes the path of an object moving in space. Find the velocity, speed, and acceleration of the object. $$ \mathbf{r}(t)=t^{2} \mathbf{i}+t \mathbf{j}+2 t^{3 / 2} \mathbf{k} $$

Use the properties of the derivative to find the following. (a) \(\mathbf{r}^{\prime}(t)\) (b) \(\mathbf{r}^{\prime \prime}(t)\) (c) \(D_{t}[\mathbf{r}(t) \cdot \mathbf{u}(t)]\) (d) \(D_{t}[3 \mathbf{r}(t)-\mathbf{u}(t)]\) (e) \(D_{t}[\mathbf{r}(t) \times \mathbf{u}(t)]\) (f) \(D_{t}[\|\mathbf{r}(t)\|], \quad t>0\) $$ \begin{array}{l} \mathbf{r}(t)=t \mathbf{i}+2 \sin t \mathbf{j}+2 \cos t \mathbf{k} \\ \mathbf{u}(t)=\frac{1}{t} \mathbf{i}+2 \sin t \mathbf{j}+2 \cos t \mathbf{k} \end{array} $$

Find the indefinite integral. $$ \int\left[(2 t-1) \mathbf{i}+4 t^{3} \mathbf{j}+3 \sqrt{t} \mathbf{k}\right] d t $$

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