Chapter 1: Problem 92
Use a calculator to approximate the value. Round your answer to two decimal places. $$ \arcsin (-0.39) $$
Chapter 1: Problem 92
Use a calculator to approximate the value. Round your answer to two decimal places. $$ \arcsin (-0.39) $$
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Get started for freeVerify that the Intermediate Value Theorem applies to the indicated interval and find the value of \(c\) guaranteed by the theorem. $$ f(x)=x^{2}+x-1, \quad[0,5], \quad f(c)=11 $$
(a) Prove that if \(\lim _{x \rightarrow c}|f(x)|=0,\) then \(\lim _{x \rightarrow c} f(x)=0\). (Note: This is the converse of Exercise \(74 .)\) (b) Prove that if \(\lim _{x \rightarrow c} f(x)=L,\) then \(\lim _{x \rightarrow c}|f(x)|=|L|\). [Hint: Use the inequality \(\|f(x)|-| L\| \leq|f(x)-L| .]\)
Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. If the inverse function of \(f\) exists, then the \(y\) -intercept of \(f\) is an \(x\) -intercept of \(f^{-1}\).
Explain why the function has a zero in the given interval. $$ \begin{array}{lll} \text { Function } & \text { Interval } \\ h(x)=-2 e^{-x / 2} \cos 2 x &{\left[0, \frac{\pi}{2}\right]} \\ \end{array} $$
In Exercises \(25-34,\) find the limit. $$ \lim _{x \rightarrow 1 / 2} x^{2} \tan \pi x $$
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