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What three assumptions must be met when you are using the \(z\) test to test differences between two means when \(\sigma_{1}\) and \(\sigma_{2}\) are known?

Short Answer

Expert verified
The assumptions are random sampling, normality of the distribution of differences, and known population standard deviations.

Step by step solution

01

Random Sampling

The first assumption when using the \(z\) test to compare two means is that the samples must be randomly selected. This ensures each member of the population has an equal chance of being included in the sample, which helps to generalize the results to the entire population.
02

Normality

The second assumption is that the distribution of the difference between the two means (\(\bar{x_1} - \bar{x_2}\)) should be approximately normal. This can be achieved if each sample is large enough (typically \(n \geq 30\)) or if the original populations are normally distributed.
03

Known Population Standard Deviations

The third assumption is that the standard deviations of both populations (\(\sigma_1\) and \(\sigma_2\)) must be known. If they are unknown, the \(z\) test is not appropriate, and a \(t\) test might be more suitable.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Sampling
When conducting a statistical analysis using the \(z\) test, one of the fundamental assumptions is random sampling. Random sampling ensures that each individual or data point in the entire population has an equal probability of being selected for the sample. This equality in selection probability is crucial to achieve unbiased results.

Imagine you're picking marbles from a big jar. If you close your eyes and mix them well before picking, you ensure a fair chance for any marble to be chosen. This is similar to how random sampling works in statistics.

  • Increases the likelihood that the sample accurately represents the population.
  • Helps make results generalizable to the broader group you're interested in.
Failure to use a random sample could lead to skewed results and incorrect conclusions. It’s important because the integrity of your conclusions hinges on the accuracy of the sampling.
Normality Assumption
A critical aspect of using a \(z\) test is meeting the normality assumption for testing differences between means. The normality assumption implies that the distribution of the difference between the sample means should be approximately normal. This condition is necessary to apply the properties of the normal distribution to your test.

There are a couple of pathways to ensure normality:
  • If each sample's size is large enough (typically \(n \geq 30\)), the Central Limit Theorem suggests that the sampling distribution of the difference in means will be approximately normal.
  • If the original populations themselves are normally distributed, even small samples should reflect normality in their sampling distributions.
Meeting this assumption helps statisticians work with the predictability of the normal curve, making it easier to make valid statistical inferences.
Known Standard Deviations
The requirement for known standard deviations in the \(z\) test is what often distinguishes it from the \(t\) test. For a \(z\) test, it is assumed that the standard deviations of the two populations you’re examining, \(\sigma_{1}\) and \(\sigma_{2}\), are known.

  • Having known standard deviations helps in calculating the standard error of the means precisely.
  • If the standard deviations are unknown, using the \(z\) test becomes inappropriate.
In cases where standard deviations cannot be precisely obtained, the \(t\) test becomes a more fitting option because it accommodates such scenarios by estimating these values directly from sample data. Ensuring you have accurate measures of variability in your populations enhances the reliability of your testing outcomes.

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Most popular questions from this chapter

Weights of Running Shoes The weights in ounces of a sample of running shoes for men and women are shown. Test the claim that the means are different. Use the \(P\) -value method with \(\alpha=0.05 .\) $$ \begin{array}{ll|ccc}{\text { Men }} & {} & {\text { Women }} & {} \\ \hline 10.4 & {12.6} & {10.6} & {10.2} & {8.8} \\ {1.1} & {14.7} & {9.6} & {9.5} & {9.5} \\ {10.8} & {12.9} & {10.1} & {11.2} & {9.3} \\ {11.7} & {13.3} & {9.4} & {10.3} & {9.5} \\ {12.8} & {14.5} & {9.8} & {10.3} & {11.0} \\\ \hline\end{array} $$

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For Exercises 7 through \(27,\) perform these steps. a. State the hypotheses and identify the claim. b. Find the critical value(s). c. Compute the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. Animal Bites of Postal Workers In Cleveland, a random sample of 73 mail carriers showed that 10 had been bitten by an animal during one week. In Philadelphia, in a random sample of 80 mail carriers, 16 had received animal bites. Is there a significant difference in the proportions? Use \(\alpha=0.05 .\) Find the \(95 \%\) confidence interval for the difference of the two proportions.

For Exercises 7 through \(27,\) perform these steps. a. State the hypotheses and identify the claim. b. Find the critical value(s). c. Compute the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. Victims of Violence A random survey of 80 women who were victims of violence found that 24 were attacked by relatives. A random survey of 50 men found that 6 were attacked by relatives. At \(\alpha=0.10,\) can it be shown that the percentage of women who were attacked by relatives is greater than the percentage of men who were attacked by relatives?

Ages of Gamblers The mean age of a random sample of 25 people who were playing the slot machines is 48.7 years, and the standard deviation is 6.8 years. The mean age of a random sample of 35 people who were playing roulette is 55.3 with a standard deviation of 3.2 years. Can it be concluded at \(\alpha=0.05\) that the mean age of those playing the slot machines is less than those playing roulette?

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