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When one is computing the \(F\) test value, what condition is placed on the variance that is in the numerator?

Short Answer

Expert verified
The variance in the numerator must be the larger of the two variances.

Step by step solution

01

Understand the F-Test

The F-test is used to compare two variances to determine if they are significantly different. It is commonly used in ANOVA and regression analysis.
02

Identify the Numerator and Denominator

When conducting an F-test, you compare the variances of two samples. The variance of one sample is placed in the numerator, and the variance of the other sample is placed in the denominator.
03

Condition on the Numerator

The variance in the numerator must always be the larger of the two sample variances. This ensures that the calculated F-value is greater than or equal to 1, simplifying analysis and enabling the use of F-distribution tables which assume the numerator variance is larger.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

ANOVA
ANOVA, or Analysis of Variance, is a statistical method used to test the differences between three or more group means. It helps in identifying if at least one of the means is statistically different from the others. This approach prevents the need for multiple t-tests, which could increase the risk of making a Type I error.
  • ANOVA examines the variability between groups relative to the variability within groups.
  • The total variability is divided into components: "between-group variability" and "within-group variability."
  • If the between-group variability is significantly larger than the within-group variability, we conclude that there are genuine differences between the groups.
This method involves setting up the null hypothesis that all group means are equal, against the alternative that at least one is different. A significant F-test result suggests rejecting the null hypothesis, indicating meaningful differences between the groups. Always ensure assumptions such as normality and homogeneity of variances are met before interpreting the results.
Regression Analysis
Regression Analysis is a powerful tool for modeling the relationship between a dependent variable and one or more independent variables. It helps in predicting outcomes and understanding relationships within data.
  • The simplest form is linear regression, which models the relationship using a straight line.
  • Multiple regression involves more than one independent variable, which may affect the dependent variable.
  • Regression analysis estimates the coefficients that result in the best-fitting line or curve for predicting values.
The F-test in regression analysis plays a crucial role in determining if the model as a whole is statistically significant. Essentially, it checks whether your overall regression model explains a significant amount of variance in the dependent variable compared to a simple mean model.
Sample Variances Analysis
Analyzing sample variances is crucial in understanding the dispersion of data points within a dataset. In both ANOVA and regression analysis, comparing variances is essential for evaluating hypotheses.
  • Variance measures how far individual data points are from the mean.
  • High variance indicates data points are spread out, while low variance signifies they are close to the mean.
  • The F-test specifically compares two sample variances to determine if they differ significantly.
The larger variance should be placed in the numerator to ensure that the F-test yields a value greater than or equal to 1, facilitating easier interpretation. Accurately analyzing variances allows researchers to make informed decisions about the hypotheses they are testing, further enhancing the reliability of their statistical conclusions.

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Most popular questions from this chapter

Show two different ways to state that the means of two populations are equal.

Perform these steps. a. State the hypotheses and identify the claim. b. Find the critical value(s). c. Compute the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. According to the U.S. Bureau of Labor Statistics, approximately equal numbers of men and women are engaged in sales and related occupations. Although that may be true for total numbers, perhaps the proportions differ by industry. A random sample of 200 salespersons from the industrial sector indicated that 114 were men, and in the medical supply sector, 80 of 200 were men. At the 0.05 level of significance, can we conclude that the proportion of men in industrial sales differs from the proportion of men in medical supply sales?

Find the proportions \(\hat{p}\) and \(\hat{q}\) for each. a. \(n=52, X=32\) b. \(n=80, X=66\) c. \(n=36, X=12\) d. \(n=42, X=7\) e. \(n=160, X=50\)

Health Care Knowledge Systems reported that an insured woman spends on average 2.3 days in the hospital for a routine childbirth, while an uninsured woman spends on average 1.9 days. Assume two random samples of 16 women each were used in both samples. The standard deviation of the first sample is equal to 0.6 day, and the standard deviation of the second sample is 0.3 day. At \(\alpha=0.01,\) test the claim that the means are equal. Find the \(99 \%\) confidence interval for the differences of the means. Use the \(P\) -value method

Perform each of the following steps. a. State the hypotheses and identify the claim. b. Find the critical value(s). c. Compute the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. The average length of "short hospital stays" for men is slightly longer than that for women, 5.2 days versus 4.5 days. A random sample of recent hospital stays for both men and women revealed the following. At \(\alpha=0.01\), is there sufficient evidence to conclude that the average hospital stay for men is longer than the average hospital stay for women? $$ \begin{array}{lll} & \text { Men } & \text { Women } \\ \hline \text { Sample size } & 32 & 30 \\ \text { Sample mean } & 5.5 \text { days } & 4.2 \text { days } \\ \text { Population standard deviation } & 1.2 \text { days } & 1.5 \text { days } \end{array} $$

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