Chapter 13: Problem 29
When \(n \geq 30,\) the formula \(r=\frac{\pm z}{\sqrt{n-1}}\) can be used to find the critical values for the rank correlation coefficient. For example, if \(n=40\) and \(\alpha=0.05\) for a two-tailed test, $$ r=\frac{\pm 1.96}{\sqrt{40-1}}=\pm 0.314 $$ Hence, any \(r_{s}\) greater than or equal to +0.314 or less than or equal to -0.314 is significant. Find the critical \(r\) value for each (assume that the test is two-tailed). $$ n=50, \alpha=0.05 $$
Short Answer
Step by step solution
Identify Variables
Calculate Square Root of (n - 1)
Calculate r using Formula
Simplify the Expression
Interpret the Result
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Critical Values
To find the critical value for the correlation, you use the formula \(r = \frac{\pm z}{\sqrt{n-1}}\). The \(z\) value corresponds to the critical value from the standard normal distribution table, depending on the chosen significance level \(\alpha\). Essentially, \(r\) tells us when we should consider the rank correlation coefficient significantly different from zero, implying a relationship between the variables examined.
In the exercise example, for \(n = 50\), the critical value \(r = \pm 0.28\) means any correlation greater than or equal to \(+0.28\) or less than or equal to \(-0.28\) is deemed statistically significant.
Two-Tailed Test
In the given exercise, a two-tailed test is used. This means we are interested in deviations both above and below a critical threshold, which for many standard normal distribution applications aids in detecting any significant departure from a null hypothesis value, not just in a single direction.
- Lower tail: Tests for values significantly smaller than the expected parameter.
- Upper tail: Tests for values significantly larger than the expected parameter.
Normal Distribution
For large sample sizes, sample distributions of statistics (like the rank correlation coefficient) tend to follow a normal distribution, a result of the Central Limit Theorem. In the given textbook solution, a normal distribution is used to approximate the sampling distribution of the rank correlation coefficient for the hypothesis test, which allows the test to utilize critical values derived from the standard normal distribution. This is usually acceptable when the sample size \(n \ge 30\).
The standard normal distribution is a special form of the normal distribution with a mean of 0 and a standard deviation of 1, and tables of \(z\)-scores are used as a reference for determining critical values in many statistical tests.
Significance Level
In the given textbook exercise, the significance level is set at \(\alpha = 0.05\), which is a common choice. This means that there is a 5% risk of concluding that an effect exists when it does not.
- \(\alpha = 0.05\): Indicates that 5% of the time, you would expect to reject a true null hypothesis, or in other words, tolerate a 5% chance of making a false positive conclusion.
- Commonly accepted across many studies and fields, \(\alpha = 0.05\) strikes a balance between being too lenient and being overly strict.