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What population parameter can be tested with the sign test?

Short Answer

Expert verified
The sign test is used to test the population median.

Step by step solution

01

Understand the Sign Test

The sign test is a non-parametric test used in statistical analysis. It is mainly used to test hypotheses about the median of a single sample or the difference in medians of paired samples when the data does not necessarily follow a normal distribution.
02

Identify the Population Parameter

The population parameter that the sign test assesses is the median. Specifically, it tests whether the median of a population is equal to some hypothesized value or if there is a difference in the medians of two related samples.
03

Formulate Hypotheses

With the sign test, the null hypothesis generally states that the median of the population is equal to some specified value or that the difference in medians is zero for paired samples. The alternative hypothesis suggests an inequality or difference.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Non-Parametric Tests
Non-parametric tests like the sign test are crucial tools in statistical analysis because they do not require the assumption of normal distribution in the data. Unlike parametric tests, which depend on assumptions about the population parameters (like the mean and variance), non-parametric tests are more flexible and apply to data that do not fit these strict criteria.
These tests are primarily focused on the order or rank of data rather than the actual data values. This quality makes non-parametric tests particularly useful when dealing with outliers or skewed data. They provide a way to analyze data while ignoring these complexities, allowing for robust conclusions. For instance, in situations where you can't guarantee that your data follows a bell curve distribution, non-parametric tests come to the rescue.
The Role of Median Hypothesis in Sign Test
The sign test specifically focuses on the median, making it a vital tool when addressing the median hypothesis. In simple terms, the sign test helps us understand if the median of a particular dataset is equal to a specified value or if there is a significant change in the medians between paired samples.
The test uses signs (+ or -) instead of exact values from the data. This means we are essentially counting instances of values above or below a median value or difference.
This process involves setting up a null hypothesis that assumes no difference from the median or between pairs, and an alternative hypothesis proposing a difference either greater or less than this value. This method of hypothesis testing is straightforward and easy to apply, making it ideal for quick assessments.
Exploring Paired Samples Analysis
Paired samples analysis is a statistical technique used to compare two related groups. A common scenario is evaluating before-and-after data or matched subjects. For these comparisons to be accurate, the pairs need to be meaningfully related.
For instance, a nutritional study could measure the weight of individuals before and after a controlled diet. The data points (before vs. after) would form pairs for each study participant.
The sign test is perfect for paired samples when the normal distribution cannot be assumed. It checks if there is a significant median difference between the pairs. Instead of relying on extensive calculations or precise data distribution, the paired sign test simply considers the direction of change—whether the paired differences are positive or negative—providing insights into the overall trend.

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Most popular questions from this chapter

Find the sum of the signed ranks. Assume that the samples are dependent. State which sum is used as the test value. $$ \begin{array}{l|llllllll} \text { Pretest } & 25 & 38 & 62 & 49 & 63 & 29 & 74 & 82 \\ \hline \text { Posttest } & 29 & 45 & 51 & 45 & 71 & 32 & 74 & 87 \end{array} $$

Perform these steps. a. Find the Spearman rank correlation coefficient. b. State the hypotheses. c. Find the critical value. Use \(\alpha=0.05\). d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. Calories and Cholesterol in Fast-Food Sandwiches Use the Spearman rank correlation coefficient to see if there is a linear relationship between these two sets of data, representing the number of calories and the amount of cholesterol in randomly selected fast-food sandwiches $$ \begin{array}{l|llllllll} \text { Calories } & 580 & 580 & 270 & 470 & 420 & 415 & 330 & 430 \\ \hline \begin{array}{l} \text { Cholesterol } \\ (\mathbf{m g}) \end{array} & 205 & 225 & 285 & 270 & 185 & 215 & 185 & 220 \end{array} $$

Daily Lottery Numbers Listed below are the daily numbers (daytime drawing) for the Pennsylvania State Lottery for February 2007. Using O for odd and E for even, test for randomness at \(\alpha=0.05\). $$\begin{array}{lllllll}270 & 054 & 373 & 204 & 908 & 121 & 121 \\ 804 & 116 & 467 & 357 & 926 & 626 & 247 \\\ 783 & 554 & 406 & 272 & 508 & 764 & 890 \\ 441 & 964 & 606 & 568 & 039 & 370 & 583\end{array}$$

Perform these steps. a. Find the Spearman rank correlation coefficient. b. State the hypotheses. c. Find the critical value. Use \(\alpha=0.05\). d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. Textbook Ranking After reviewing 7 potential textbooks, an instructor ranked them from 1 to 7 , with 7 being the highest ranking. The instructor selected one of his previous students and had the student rank the potential textbooks. The rankings are shown. At \(\alpha=0.05\), is there a relationship between the rankings? $$ \begin{array}{l|ccccccc} \text { Textbook } & \mathrm{A} & \mathrm{B} & \mathrm{C} & \mathrm{D} & \mathrm{E} & \mathrm{F} & \mathrm{G} \\ \hline \text { Instructor } & 1 & 4 & 6 & 7 & 5 & 2 & 3 \\ \hline \text { Student } & 2 & 6 & 7 & 5 & 4 & 3 & 1 \end{array} $$

The 2014 women's 1000 -meter speed skating winning time was \(1: 14: 02,\) posted by Zhang Hong of China. In preparation for the 2018 Winter Olympics in Pyeongchang, South Korea several randomly selected students from two different universities posted the following times (rounded to the nearest second). Test the claim that there is no difference in times between universities at $\alpha=0.05 .$$$\begin{array}{l|llllllllll}\text { UA } & 2: 05 & 2: 15 & 1: 58 & 1: 42 & 2: 01 & 1: 40 & 1: 39 & 2: 20 & 1: 51 & 2: 03 \\ \hline \text { UB } & 2: 10 & 2: 06 & 1: 35 & 1: 48 & 1: 38 & 2: 00 & 2: 15 & 2: 14 & 2: 27 & 1: 48\end{array}$$

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