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Why is obtaining the mean and standard deviation ofxa first step in approximating the sample distribution of the sample mean by a normal distribution.

Short Answer

Expert verified

To acquire the exact form of the sampling distribution (normal distant) of the sample mean, we must first obtain the values of the sample mean's mean μxand standard deviationσx.

Step by step solution

01

Given Information

We have To find The reason is obtaining the mean and standard deviation of xa First step in approximating the sampling distribution of the sample mean by a normal distribution.

02

Explanation

Means μand standard deviation σare the parameters of the normal distribution. The values of these parameters μ&σare required to establish the exact form of the normal distortion.

To acquire the exact form of the sampling distribution (normal distant) of the sample mean, we must first obtain the values of the sample mean's mean μxand standard deviation σx

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Most popular questions from this chapter

Relative to the population mean, what happens to the possible sample means for samples of the same size as the sample size increases? Explain the relevance of this property in estimating a population means by a sample mean.

Ethanol Railroad Tariffs. An ethanol railroad tariff is a fee charged for shipments of ethanol on public railroads. The Agricultural Marketing Service publishes tariff rates for railroad-car shipments of ethanol in the Biofuel Transportation Database. Assuming that the standard deviation of such tariff rates is \(1,150, determine the probability that the mean tariff rate of 500randomly selected railroad car shipments of ethanol will be within \)100of the mean tariff rate of all railroad-car shipments of ethanol. Interpret your answer in terms of sampling error.

Consider simple random samples of size n without replacement from a population of size N.

Part (a): Show that if n0.05N,then0.97N-nN-11,

Part (b): Use part (a) to explain why there is little difference in the values provided by Equations (7.1)and (7.2)when the sample size is small relative to the population size- that is, when the size of the sample does not exceed 5% of the size of the population.

Part (c): Explain why the finite population correction factor can be ignored and the simpler formula, Equation (7.2), can be used when the sample size is small relative to the population size.

Part (d): The term N-n/N-1is known as the finite population correction factor. Can you explain why?

Officer Salaries. Refer to Problem 5.

a. Use the answer you obtained in Problem 5(b)and Definition 3.11on page 140 to find the mean of the variable x^Interpret your answer.

b. Can you obtain the mean of the variable ix without doing the calculation in part (a)? Explain your answer.

Population data: 1,2,3,4.

Part (a): Find the mean, μ, of the variable.

Part (b): For each of the possible sample sizes, construct a table similar to Table 7.2on the page 238and draw a dotplot for the sampling for the sampling distribution of the sample mean similar to Fig 7.1on page 293.

Part (c): Construct a graph similar to Fig 7.3and interpret your results.

Part (d): For each of the possible sample sizes, find the probability that the sample mean will equal the population mean.

Part (e): For each of the possible sample sizes, find the probability that the sampling error made in estimating the population mean by the sample mean will be 0.5or less, that is, that the absolute value of the difference between the sample mean and the population mean is at most 0.5.

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