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NBA ChampsThe winner of the 2012-2013 National Basketball Association (NBA) championship was the Miami Heat. One possible starting lineup for that team is as follows.

a. Determine the population mean height, μ, of the five players:

b. Consider samples of size 2 without replacement. Use your answer to Exercise 7.11(b) on page 295 and Definition 3.11 on page 140 to find the mean, μx¯, of the variable x¯.

c. Find μx¯using only the result of part (a).

Short Answer

Expert verified

Part a. The population mean height of the five players is μ=78.6.

Part b. The mean of the variable x¯when the sample size is 2 is role="math" localid="1652628045147" μx¯=78.6.

Part c.μx¯=78.6.

Step by step solution

01

Part (a) Step 1. Given Information

We are given a data in the table as

And we need to find the population mean of the data.

02

Part (a) Step 2. Find the population mean

From the table, the population data is given as 83,76,80,74,80.

So the population mean height for the five players is given as

μ=83+76+80+74+805μ=3935μ=78.6

03

Part (b) Step 2. Find the mean when sample size is 2

For the population data: 83,76,80,74,80.

The sample and sample mean for a sample of size n=2are shown in the table below.

Samplex¯
83,7683+762=79.5
83,8083+802=81.5
83,7483+742=78.5
83,8083+802=81.5
76,8076+802=78
76,7476+742=75
76,8076+802=78
80,7480+742=77
80,8080+802=80
74,8074+802=77

The variable x¯has the following mean

μx¯=79.5+81.5+78.5+81.5+78+75+78+77+80+7710μx¯=78610μx¯=78.6

So when the sample size is 2, the variable x¯has a mean μx¯=78.6.

04

Part (c) Step 1. Find the sample mean when sample size is 2

We know that mean of the sample mean is equal to the population mean irrespective of the sample size.

Here, the population mean is μ=78.6.

So the mean of the sample mean of sample size 2 is

μx¯=μ=78.6

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Most popular questions from this chapter

Repeat parts (b)-(e) of Exercise 7.11 for samples of size3.

A variable of a population has mean μand standard deviation σFor a large sample size n, fill in the blanks, Justify your answers.

a. Approximately _ %of all possible samples have means within σ/nof the population mean, μ.

b. Approximately _ %of all possible samples have means within 2σ/nof the population mean, μ

c. Approximately _ %of all possible samples have means within 3σ/nof the population mean, μ

d. Approximately __ %of all possible samples have means within zv/2of the population mean, μ

Ethanol Railroad Tariffs. An ethanol railroad tariff is a fee charged for shipments of ethanol on public railroads. The Agricultural Marketing Service publishes tariff rates for railroad-car shipments of ethanol in the Biofuel Transportation Database. Assuming that the standard deviation of such tariff rates is \(1,150, determine the probability that the mean tariff rate of 500randomly selected railroad car shipments of ethanol will be within \)100of the mean tariff rate of all railroad-car shipments of ethanol. Interpret your answer in terms of sampling error.

In Example 7.5, we used the definition of the standard deviation of a variable to obtain the standard deviation of the heights of the five starting players on a men's basketball team and also the standard deviation of x for samples of sizes 1,2,3,4,5.The results are summarized in Table 7.6on page 298. Because the sampling is without replacement from a finite population, Equation (7.1) can also be used to obtain σx.

Part (a): Apply Equation (7.1) to compute σx for sample sizes of 1,2,3,4,5. Compare your answers with those in Table 7.6.

Part (b): Use the simpler formula, Equation (7.2) to compute σx for samples of sizes 1,2,3,4,5.Compare your answers with those in Table 7.6. Why does Equation (7.2)generally yield such poor approximations to the true values?

Part (c): What percentages of the population size are samples of sizes 1,2,3,4,5.

Population data: 2,5,8

Part (a): Find the mean, μof the variable.

Part (b): For each of the possible sample sizes, construct a table similar to Table 7.2on the page 293and draw a dotplot for the sampling for the sampling distribution of the sample mean similar to Fig 7.1on page 293.

Part (c): Construct a graph similar to Fig 7.3and interpret your results.

Part (d): For each of the possible sample sizes, find the probability that the sample mean will equal the population mean.

Part (e): For each of the possible sample sizes, find the probability that the sampling error made in estimating the population mean by the sample mean will be0.5or less, that is, that the absolute value of the difference between the sample mean and the population mean is at most 0.5.

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