Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The winner of the 2012-2013 National Basketball Association (NBA) championship was the Miami Heat, One possible starting lineup for that team is as follows:

Part (a): Find the population mean height of the five players.

Part (b): For samples of size 2, construct a table similar to Table 7.2 on page 293. Use the letter in parentheses after each player's name to represent each player.

Part (c): Draw a dotplot for the sampling distribution of the sample mean for samples of size 2.

Part (d): For a random sample of size2, what is the chance that the sample mean will equal the population mean?

Part (e): For a random sample of size 2, obtain the probability that the sampling error made in estimating the population mean by the sample mean will be1 inch or less; that is, determine the probability that x will be within1 inch of μ. Interpret your result in terms of percentages.

Short Answer

Expert verified

Part (a): The mean population of the five players is 78.6inches.

Part (b): Constructing the table of samples of size 2 of the given population is given below,


Part (c): The dot plot is given below,


Part (d): The chance that sample mean is equal to population mean is 0.

Part (e): The probability that x is within 1 inch of μis 0.4.

Step by step solution

01

Part (a) Step 1. Given information

Consider the given question,

02

Part (a) Step 2. Find the mean for five people.

The mean for five people is given below,

μ=i=1nxiN=83+76+80+74+805=3935=78.6

Thus, the population mean height for five players is78.6inches.

03

Part (b) Step 1. Construct samples of size 2 of the given population.

The samples of size 2 and the corresponding means are obtained,


Here, Chrish Bosh is represented by B, Dwyane Wade is represented by W, LeBron James is represented by J, Mario Chalmers is represented by C and Udonis Haslem is represented by H.

04

Part (c) Step 1. Construct the dot plot.

On constructing the dot plot for the sampling distribution of the sample mean,

05

Part (d) Step 1. Find the chance that the sample mean will equal the population mean.

We need to find the Px=μ.

From the table obtained in part (b), it is clear that none of the sample means is equal to the population mean.

Also, the number of samples of size 2 is 10.

Px=μ=010=0

06

Part (e) Step 1. Find the probability that x will be within 1 inch of μ.

We need to find the Pμ-1xμ+1.

From the table obtained in part (b), it is clear 4 of the sample means within 1 inch of the population mean.

Pμ-1xμ+1=P(78.6-1x78.6+1)=P(77.6x79.6)=410=0.4

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A variable of a population has mean μ and standard deviationσ. that For a large sample size n, answer the following questions.

a. Identify the distribution ofx.

b. Does your answer to part (a) depend on n being large? Explain your answer.

c. Identify the mean and the standard deviation ofx.

d. Does your answer to part (c) depend on the sample size being large? Why or why not?

Nurses and Hospital Stays. In the article "A Multifactorial Intervention Program Reduces the Duration of Delirium. Length of Hospitalization, and Mortality in Delirious Patients (Journal of the American Geriatrics Society, Vol. 53. No. 4. pp. 622-628), M. Lundstrom et al. investigated whether education programs for nurses improve the outcomes for their older patients. The standard deviation of the lengths of hospital stay on the intervention ward is 8.3days.

a. For the variable "length of hospital stay," determine the sampling distribution of the sample mean for samples of 80patients on the intervention ward.

b. The distribution of the length of hospital stay is right-skewed. Does this invalidate your result in part (a)? Explain your answer.

c. Obtain the probability that the sampling error made in estimating the population means length of stay on the intervention ward by the mean length of stay of a sample of 80patients will be at most 2days.

7.44 NBA Champs. Repeat parts (b) and (c) of Exercise 7.41 for samples of size 4. For part (b), use your answer to Exercise 7.14.

A variable of a population has a mean of μ=35and a standard deviation of σ=42.

a. If the variable is normally distributed, identify the sampling distribution of the sample mean for samples of size 9.

b. Can you answer part (a) if the distribution of the variable under consideration is unknown? Explain your answer.

c. Can you answer part (a) if the distribution of the variable under consideration is unknown but the sample size is 36instead of 9?

Why or why not?

Explain why increasing the sample size tends to result in a smaller sampling error when a sample means is used to estimate a population mean.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free