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Officer Salaries. Refer to Problem 5.

a. Use the answer you obtained in Problem 5(b)and Definition 3.11on page 140 to find the mean of the variable x^Interpret your answer.

b. Can you obtain the mean of the variable ix without doing the calculation in part (a)? Explain your answer.

Short Answer

Expert verified

Part (a) The mean of the variable (x¯)is 18$1000s

Part (b) Yes.

Step by step solution

01

Part (a) Step 1: Given information

From the population of six officers, 15 size 4 samples are possible. The first column in the following table lists them.

02

Part (a) Step 2: Concept

Formula used:μx¯=x¯N

03

Part (a) Step 3: Calculation

Obtain the mean of the variable (x¯)

μx¯=x¯N=14+15+16+16+17+18+17+18+19+20+18+19+20+21+2215=27015=18

Thus, for sample size 4, the mean μx¯ of all potential sample mean wages is 18 $1000s.

04

Part (b) Step 1: Explanation

Yes, the mean of the variable (x¯) may be calculated because the mean for sampling sample means is the same as the population mean (μ) As a result, the population mean is $18.0 thousand dollars.

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Most popular questions from this chapter

Consider simple random samples of size n without replacement from a population of size N.

Part (a): Show that if n0.05N,then0.97N-nN-11,

Part (b): Use part (a) to explain why there is little difference in the values provided by Equations (7.1)and (7.2)when the sample size is small relative to the population size- that is, when the size of the sample does not exceed 5% of the size of the population.

Part (c): Explain why the finite population correction factor can be ignored and the simpler formula, Equation (7.2), can be used when the sample size is small relative to the population size.

Part (d): The term N-n/N-1is known as the finite population correction factor. Can you explain why?

7.45 NBA Champs. Repeat parts (b) and (c) of Exercise 7.41for samples of size 5. For part (b). use your answer to Exercise 7.15(b).

Young Adults at Risk. Research by R. Pyhala et al. shows that young adults who were born prematurely with very low birth weights (below 1500 grams) have higher blood pressure than those born at term. The study can be found in the article. "Blood Pressure Responses to Physiological Stress in Young Adults with Very Low Birth Weight" (Pediatrics, Vol. 123, No, 2, pp. 731-734 ). The researchers found that systolic blood pressures, of young adults who were born prematurely with very low birth weights have mean 120.7 mm Hg and standard deviation 13.8 mm Hg.
a. Identify the population and variable.
b. For samples of 30 young adults who were born prematurely with very low birth weights, find the mean and standard deviation of all possible sample mean systolic blood pressures. Interpret your results in words.
c. Repeat part (b) for samples of size 90.

7.67 Brain Weights. In 1905, R. Pearl published the article "Biometrical Studies on Man. 1. Variation and Correlation in Brain Weight" (Biometrika, Vol. 4, pp. 13-104). According to the study, brain weights of S wedish men are normally distributed with a mean of 1.40kg and a standard deviation of 0.11kg

a. Determine the sampling distribution of the sample mean for samples of size 3 Interpret your answer in terms of the distribution of all possible sample mean brain weights for samples of three Swedish men.

b. Repeat part (a) for samples of size 12

c. Construct graphs similar to those shown in Fig. 7.4on page 304 .

d. Determine the percentage of all samples of three Swedish men that have mean brain weights within 0.1kg of the population mean brain weight of 1.40kg. Interpret your answer in terms of sampling error.

e. Repeat part (d) for samples of size 12

You have seen that the larger the sample size, the smaller the sampling error tends to be in estimating a population means by a sample mean. This fact is reflected mathematically by the formula for the standard deviation of the sample mean: σi=σ/n. For a fixed sample size, explain what this formula implies about the relationship between the population standard deviation and sampling error.

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