Question

Suppose that A and B are events such that $P\left(A\right)=0.84$$P\left(B\right)=0.46$and $P(A\&D)=0.30$Determine $P(AorB)$.

Short answer

$P(A\cup B)=0.92$

Step-by-step solution

Step 1. Given information.  

$$\begin{gathered} P\left(A\right)=0.84 \\ P\left(B\right)=0.46 \\ P(A\&B)=0.38 \end{gathered}$$

Step 2. Calculate the probability in the following manner.

$$\begin{gathered} P(A\cup B)=P\left(A\right)+P\left(B\right)-P(A\cap B) \\ P(A\cup B)=0.84+0.46-.0.38 \\ P(A\cup B)=0.92 \end{gathered}$$