Question

Suppose that C and D are mutually exclusive events such that $P\left(C\right)=0.14$and$P\left(D\right)=0.32$ Determine $P(CorD)$.

Short answer

As a result, $P(CorD$has a value of$0.46$

Step-by-step solution

Step 1. Given information.  

$$\begin{gathered} P\left(C\right)=0.14 \\ P\left(D\right)=0.32 \end{gathered}$$

Step 2. P(C and D ) is zero for mutually exclusive events.

The following formula is used to determine $P(CorD)$

$$\begin{gathered} P(CorD)=P\left(C\right)+P\left(D\right) \\ 0.14+0.32 \\ 0.46 \end{gathered}$$

As a result, $P(CorD)$has a value of $0.46$