Question

Suppose that A and B are mutually exclusive events such that $P\left(A\right)=0.25andP\left(B\right)=0.40$Determine$P(AorB)$.

Short answer

As a result, $P(AandB)$has a value of$0.65$

Step-by-step solution

Step 1. Given information. 

$$\begin{gathered} P\left(A\right)=0.25 \\ P\left(B\right)=0.4 \end{gathered}$$

Step 2. P(A and B) is zero for mutually exclusive events.

The following formula is used to determine $P(AandB)$:

$$\begin{gathered} P(AorB)=P\left(A\right)+P\left(B\right) \\ 0.25+0.4 \\ =0.65 \end{gathered}$$

As a result, $P(AandB)$has a value of$0.65$