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The intent is to employ the sample data to perform a hypothesis test to compare the means of the two populations from which the data were obtained. In each case, decide which of the procedures should be applied.

Independent: n1=20

n2=15

Short Answer

Expert verified

None of the tests is applicable for the given sample.

Step by step solution

01

Given information

The given independent sample has

n1=20

n2=15

02

Explanation

The independent sample has size, n1=20

n2=15

The assumptions for a pooled t-test:

1. A basic random sample from two populations will be chosen.

2. The samples chosen are self-contained.

3. The population is roughly normal.

4. The standard deviations of the populations are the same.

The assumptions for a non-pooled t-test:

1. A basic random sample from two populations will be chosen.

2. The samples chosen are self-contained.

3. The population is roughly normal.

4. It is not necessary for the standard deviations of populations to be equal.

The assumptions for the paired t-test:

1. The chosen sample should be a simple paired sample.

2. The difference is about average.

3. There is a vast population.

The data in the above graph is not regularly distributed.

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Most popular questions from this chapter

The intent is to employ the sample data to perform a hypothesis test to compare the means of the two populations from which the data were obtained. In each case, decide which of the procedures should be applied.

Independent: n1=17

n2=17

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The intent is to employ the sample data to perform a hypothesis test to compare the means of the two populations from which the data were obtained. In each case, decide which of the procedures should be applied.

Paired: n=18.

V. Tangpricha et al. did a study to determine whether fortifying orange juice with Vitamin D would result in changes in the blood levels of five biochemical variables. One of those variables was the concentration of parathyroid hormone (PTH), measured in picograms/milliliter ( pg/ml ). The researchers published their results in the paper "Fortification of Orange Juice with Vitamin D: A Novel Approach for Enhancing Vitamin D Nutritional Health" (American Journal of Clinical Nutrition, Vol. 77, pp. 1478-1483). Concentration levels were recorded at the beginning of the experiment and again at the end of 12weeks. The following data, based on the results of the study, provide the decrease (negative values indicate an increase) in PTH levels, in pg/ml, for those drinking the fortified juice and for those drinking the unfortified juice.

At the 5% significance level, do the data provide sufficient evidence to conclude that drinking fortified orange juice reduces PTH level more than drinking unfortified orange juice? (Note: The mean and standard deviation for the data on fortified juice are 9.0pg/mL and 37.4pg/mL, respectively, and for the data on unfortified juice, they are 1.6pg/mLand34.6pg/mL, respectively.)

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