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A variable of two populations has a mean of 7.9and standard deviation of 5.4for one of the populations and a mean of 7.1and a standard deviation of 4.6for the other population.

a. For independent samples of sizes 3and 6respectively find the mean and standard deviation of x1¯-x2¯

b. Must the variable under consideration be normally distributed on each of the two populations for you to answer part (a)? Explain your answer.

b. Can you conclude that the variable localid="1652696712667" x1¯-x2¯is normally distributed? Explain your answer.

Short Answer

Expert verified

Part a. For the variable x1¯-x2¯, the mean is 0.8and the standard deviation is 3.64.

Part b. The variable under consideration may or may not be normally distributed on each of the two populations for us to answer part (a).

Part c. No, it cannot be concluded that the variablex1¯-x2¯ is normally distributed.

Step by step solution

01

Part (a) Step 1. Given Information

We are given data of two populations:

For the first population, the sample size is n1=3, mean is μ1=7.9, and the standard deviation is σ1=5.4.

For the second population, the sample size isn2=6, mean isμ2=7.1, and the standard deviation is σ2=4.6.

02

Part (a) Step 2. Find the mean and standard deviation

The mean for the variable x1¯-x2¯is given as

μx1¯-x2¯=μ1-μ2μx1¯-x2¯=7.9-7.1μx1¯-x2¯=0.8

And the standard deviation is given as

σx1¯-x2¯=σ12n1+σ22n2σx1¯-x2¯=5.423+4.626σx1¯-x2¯=9.72+3.53σx1¯-x2¯3.64

03

Part (b) Step 1. Tell whether variables are normally distributed

The formulas in part (a) can be used regardless of the distributions of the variables of the two populations.

So the variables under consideration may or may not be normally distributed on each of the two populations.

04

Part (c) Step 1. Is the variable x1¯-x2¯ normally distributed

If the variable is normally distributed on each of the two populations then only it can be concluded that the variable x1¯-x2¯is normally distributed.

Also, the sample size is small so the distribution type matters.

Thus it cannot be concluded for sure that the variable x1¯-x2¯is normally distributed.

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Most popular questions from this chapter

In each of Exercises 10.35-10.38, we have provided summary statistics for independent simple random samples from two populations. Preliminary data analyses indicate that the variable under consideration is normally distributed on each population. Decide, in each case, whether use of the pooled t-lest and pooled t-interval procedure is reasonable. Explain your answer.
10.35 x¯1=468.3,s1=38.2,n1=6

x2=394.6,s2=84.7,n2=14

V. Tangpricha et al. did a study to determine whether fortifying orange juice with Vitamin D would result in changes in the blood levels of five biochemical variables. One of those variables was the concentration of parathyroid hormone (PTH), measured in picograms/milliliter ( pg/ml ). The researchers published their results in the paper "Fortification of Orange Juice with Vitamin D: A Novel Approach for Enhancing Vitamin D Nutritional Health" (American Journal of Clinical Nutrition, Vol. 77, pp. 1478-1483). Concentration levels were recorded at the beginning of the experiment and again at the end of 12weeks. The following data, based on the results of the study, provide the decrease (negative values indicate an increase) in PTH levels, in pg/ml, for those drinking the fortified juice and for those drinking the unfortified juice.

At the 5% significance level, do the data provide sufficient evidence to conclude that drinking fortified orange juice reduces PTH level more than drinking unfortified orange juice? (Note: The mean and standard deviation for the data on fortified juice are 9.0pg/mL and 37.4pg/mL, respectively, and for the data on unfortified juice, they are 1.6pg/mLand34.6pg/mL, respectively.)

H2*μ1μ2

H2:μ1<μ2

In each of Exercises 10.75-10.80, we have provided summary statistics for independent simple random samples form non populations. In each case, use the non pooled t-fest and the non pooled t-interval procedure to conduct the required hypothesis test and obtain the specified confidence interval.

x~1=20,s1=4,n1=10,x~2=18,s2=5,n2=15.

a. Right-tailed test,localid="1651298373729" α=0.05.

b. 90%confidence interval.

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