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Chapter 11: Q.11.3 (page 459)

Is a population proportion a parameter or a statistic? What about a sample proportion? Explain your answers.

Short Answer

Expert verified

Population proportion is a parameter.

Sample proposition is a statistic.

Step by step solution

01

Given information

Given in the question that, we need to find that whether a population proportion is a parameter or a statistic.

02

Explanation

Parameter :A parameter is a value that is calculated from a set of data.

Statistic :A statistic is a numerical value derived from a sample.

As the population proportion is a descriptive measure of population, it is obvious that it is a parameter. Because it is a descriptive measure of sample, the sample proposition is a statistic.

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Most popular questions from this chapter

Buckling Up. Refer to Exercise $11.109$ and find and interpret a $99 %$ confidence interval for the difference between the proportions of seat-belt users for drivers in the age groups $16 - 24$ years and 25-69 years.

In this Exercise, we have given the number of successes and the sample size for a simple random sample from a population. In each case,

a. use the one-proportion plus-four z-interval procedure to find the required confidence interval.

b. compare your result with the corresponding confidence interval found in Exercise $11.25 - 11.30$ , if finding such a confidence interval was appropriate.

role="math" localid="1651325715651" $x = 8, n = 40, 95 % level$

we have given the members of successes and the sample sizes for simple nunulom samples for independent random samples from two populations. In each case,

a. use the noo-proportions plus-four z-internal procedure to find the wquimal confidence interval for the difference between the nov population proportions.

b. compare your resalt with the corresponding confidence interval found in pards (d) of Exencien 11. 100-11.105, if finding such $d$ confidence intenal was appropriate.

$x_{1} = 10, n_{1} = 20, x_{2} = 18, n_{2} = 30; 80 %$ confidence interval

$x_{1} = 18, n_{1} = 30, x_{2} = 10, n_{2} = 20; 95 %$ confidence interval

A Wall Street Journal article, titled "Hypertension Drug Linked to Cancer," reported on a study of several types of high-blood-pressure drugs and links to cancer. For one type, called calcium-channel blockers, $27$ of $202$ elderly patients taking the drug developed cancer. For another type, called beta-blockers, $28$ of $424$ other elderly patients developed cancer. Find a $90 %$ confidence interval for the difference between the cancer rates of elderly people taking calcium-channel blockers and those taking beta-blockers. Note: The results of this study were challenged and questioned by several sources that claimed, for example, that the study was flawed and that several other studies have suggested that calcium-channel blockers are safe.

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