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Margin of error=0.01

Confidence level=90%

Educated guess=0.9

(a) Obtain a sample size that will ensure a margin of error of at most the one specified (provided of course that the observed value of the sample proportion is further from 0.5that of the educated guess.

(b). Compare your answer to the corresponding one and explain the reason for the difference, if any.

Short Answer

Expert verified

(a) The required sample size is 2,436.

(b) When compared to the sample size obtained in11.34 , the sample size obtained in component an is smaller. since in part an informed guess is used, resulting in a more accurate sample, whereas in 11.34the constant 0.25is used, resulting in a bigger sample.

Step by step solution

01

Part (a) Step 1: Given information

Margin of error=0.01

Confidence level=90%

Educated guess=0.9

02

Part (a) Step 2: Explanation

When the margin of error is 0.01and the confidence level is 90%, calculate the sample size.

With a 90%confidence level, the required value of za2from table areas under the standard normal curve is 1.645.

The sample size is

n=0.9(1-0.9)za¯E2

=0.9(1-0.9)1.6450.012

=0.01(27,060.25)

=2,435.4225

2,436.

03

Part (b) Step 1: Given information

Margin of error=0.01

Confidence level90%

Educated guess=0.9

04

Part (b) Step 2: Explanation

When the margin of error is 0.01and the confidence level is 90%, calculate the sample size. With a 90%confidence level, the required value of za2from table areas under the standard normal curve is 1.645.

The sample size is

n=0.25za2E2

=0.251.6450.012

=0.25(27,060.25)

=6,765.06

6,766.

When compared to the sample size obtained in 11.34, the sample size obtained in component an is smaller. since in part an informed guess is used, resulting in a more accurate sample, whereas in 11.34 the constant 0.25 is used, resulting in a bigger sample.

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