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Margin of error=0.02

Confidence level=95%

Educated guess=0.6

(a) Obtain a sample size that will ensure a margin of error of at most the one specified (provided of course that the observed value of the sample proportion is further from 0.5that of the educated guess.

(b). Compare your answer to the corresponding one and explain the reason for the difference, if any.

Short Answer

Expert verified

(a) The required sample size is 2,305.

(b) When compared to the sample size obtained in 11.32, the sample size obtained in part an is less. because the educated guess is utilised in part, which produces a more accurate sample, whereas the constant 0.25is used in , which provides a bigger sample.

Step by step solution

01

Part (a) Step 1: Given information

Margin of error=0.02

Confidence level=95%

Educated guess=0.6

02

Part (a) Step 2: Explanation

From the given values

When the margin of error is 0.02and the confidence level is 95%, calculate the sample size.

With a 95%confidence level, the required value of za2from table areas under the standard normal curve is 1.96.

The sample size is

n=0.6(1-0.6)zα2E2

=0.6(1-0.6)1.960.022

=0.24(9,604)

=2,305.96

2,305.

03

Part (b) Step 1: Given information

Margin of error=0.02

Confidence level =95%

Educated guess =0.6

04

Part (b) Step 2: Explanation

From the given data

When the margin of error is 0.02and the confidence level is 95%, calculate the sample size.

With a 95%confidence level, the required value of za2from table areas under the standard normal curve is 1.96.

The sample size is

n=0.25za2E2

=0.251.960.022

=0.25(9,604)

=2,401.

When compared to the sample size obtained in 11.32, the sample size obtained in part an is less. because the educated guess is utilised in part, which produces a more accurate sample, whereas the constant 0.25 is used in , which provides a bigger sample.

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Most popular questions from this chapter

IMR in Singapore. The infant mortality rate (IMR) is the number of infant deaths per 1000 live births. Suppose that you have been commissioned to estimate the IMR in Singapore. From a random sample of 1109live births in Singapore, you find that 0.361%of them resulted in infant deaths. You next find a 90%confidence interval:

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