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Exercis4.163

The data from Exercise 4.80 for volume, in cubic feet, and diameter at breast height, in inches, for 70 shortleaf pines are on the WeissStats site.

a. construct a scatterplot for the data.

b. decide whether using the rank correlation coefficient is reasonable.

c. decide whether using the linear correlation coefficient is reasonable.

d. find and interpret the rank correlation coefficient.

Short Answer

Expert verified

(a)


(b) The rank correlation is reasonable.

(c) The linear correlation coefficient is not reasonable.

(d) The rank correlation coefficient has a value of $0.988$. It shows that the variables rankdiameter and rankvolume have a strong positive linear connection.

Step by step solution

01

Part (a)Step 1: Given information

Given in the question that , From exercise 4.163

The data from Exercise 4.80 for volume, in cubic feet, and diameter at breast height, in inches, for 70 shortleaf pines are on the WeissStats site.

We need to construct a scatterplot for the data.

02

Part(a) Step 2: Explanation

Pines, shortleaf The WeissStats site has data from Exercise 4.80 for volume in cubic feet and diameter at breastheight in inches for 70 shortleaf trees.

Calculation:

Procedure for MINITAB:

Using MINITAB, create a scatterplot for the supplied data.

Given information:

Step 1: Select Scatterplot > Graph.

Step 2: Click OK after selecting With Connect Line.

Step 3: Create a Volume column under Y variables.

Step 4: Create a Diameter column under X variables.

Step 5: Click the OK button.

OUTPUT FROM MINITAB:

It is clear from the graph that time and score have a negative linear connection.

03

Part(b) Step 1: Given information

Given in the question that , From exercise 4.163

The data from Exercise 4.80 for volume, in cubic feet, and diameter at breast height, in inches, for 70 shortleaf pines are on the WeissStats site.

We need to decide that whether the use of rank correlation coefficient is reasonable.

04

Part (b) Step 2: Explanation

Because the variable diameter grows as the variable volume increases, the rank correlation coefficient is reasonable. That is, smaller diameter values are associated to smaller volume values, and bigger diameter values are related to larger volume values.

05

Part(c) Step 1: Given information

Given in the question that , From exercise 4.163

The data from Exercise 4.80 for volume, in cubic feet, and diameter at breast height, in inches, for 70 shortleaf pines are on the WeissStats site.

We need to decide that whether the use of linear correlation coefficient is reasonable.

06

Part(c) Step 2: Explanation

Because there is a convex upward curved pattern, and the variable diameter rises as the variable volume increases, utilising the linear correlation coefficient is not logical. As a result, the data does not appear to represent a linear pattern.

07

Part(d) Step 1: Given information

Given in the question that , From exercise 4.163

The data from Exercise 4.80 for volume, in cubic feet, and diameter at breast height, in inches, for 70 shortleaf pines are on the WeissStats site.

We need to find and interpret the rank correlation coefficient.

08

Part(d) Step 2: Explanation

Using MINITAB, find the rank for diameter and volume first.

Step 1: Select Data >Rank in the MINITAB method.

Step 2: Select Diameter in Rank data in.

Step 3: Select Rank diameter from the Store Ranks in menu.

Step 4: Select Volume in Rank data in.

Step 5: Select Rank volume from the Store Ranks in menu.

Correlation:

Procedure for MINITAB:

Step 1: Choose Stat >Basic Statistics > Correlation from the drop-down menu.

Step 2: Select Rank diameter and Rank volume from the left-hand box in Variables.

Step 3: Press the OK button.

OUTPUT FROM MINITAB:

Rank diameter and Rank Volume are related.

Pearson correlation of Rank Diameter and Rank Volume=0.988

P-Value=0.000

=0.988

The rank correlation coefficient obtained from MINITAB is $0.988$.

Interpretation: The rank correlation coefficient has a value of $0.988$. It shows that the variables rank diameter and rank volume have a strong positive linear connection.

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Most popular questions from this chapter

What is one purpose of the linear correlation coefficient?

4.78 Gas Guzzlers. The magazine Consumer Reports publishes information on automobile gas mileage and variables that affect gas mileage. In one issue, data on gas mileage (in miles per gallon) and engine displacement (in liters) were published for 121vehicles. Those data are available on the Weiss Stats site.

a. Obtain a scatterplot for the data.

b. Decide whether finding a regression line for the data is reasonable. If so, then also do parts (c) (f).

In Exercise 4.10, we give linear equations. For each equation,

a. find the y-intercept and slope.

b. determine whether the line slopes upward, slopes downward, or is horizontal, without graphing the equation.

c. use two points to graph the equation.

y=-0.75x-5

Tine Series. A collection of observations of a variable y taken at regular intervals over time is called a time series. Bocoomsic data and electrical signals are examples of time series. We can think of a time series as providing data points x1+y2where x0is the ith observation time and yiis the observed value of y at time xi. If a time series exhibits a linear trend, we can find that trend by determining the regression equation for the data points. We can then use the regression equation for forecasting purposes.

As an illustration, consider the data on the WeissStats site that shows the U.S. population, in millions of persons, for the years 1900 2013. as provided by the I.S. Census Beret.

a. Use the technology of your choice to lesbian a scatterplot of the data.

h. Use the technology of your choice to find the regression equation.

6. Use your result from part (b) to forecast the U.S. population for the years 2014 and 2015 .

For each exercise, determine the linear correlation coefficient using

a. Definition 4.8on page 183

b. Format 4.3on page 185,

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