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Hooke's Law. According to Hooke's law for springs, developed by Robert Hooke (1635-1703), the force exerted by a spring that has been compressed to a length xis given by the formula F=-kx-x0, where x0is the natural length of the spring and kis a constant, called the spring constant. A certain spring exerts a force of 32lbwhen compressed to a length of 2ftand a force of 16lbwhen compressed to a length of 3ft. For this spring, find the following

a. The linear equation that relates the force exerted to the length compressed

b. The spring constant

c. The natural length of the spring

Short Answer

Expert verified

(a) The linear equation is, F=16x-4

(b) The spring constant is, k=16

(c) The natural length is,x0=4

Step by step solution

01

Part (a) Step 1: Given information

We need to find out the corresponding linear equation.

02

Part (a) Step 2: Simplify

The equation is,F=-k(x-x0)

Now,

If x=2, then F=32

Therefore,

localid="1651003703832" 32=-k(2-x0)k=32x0-2

Similarly if x=3then F=16

Therefore, 16=-k3-x0

As the value of kis given above

So, the equation becomes,

16=-32x0-2×3-x016x0-2=-323-x016x0-32=32x0-9616x0=64x0=4

Now,

k=32x0-2=324-2=16

Hence, The required linear equation is,

F=k(x-x0)F=16(x-4)

03

Part (a) Step 3: Explanation

Here, Fis the force experienced by spring

And xis the length of spring compressed

And x0is the natural length of spring

And kis spring constant

04

Part (b) Step 1: Given information

We need to find the value of spring constant

05

Part (b) Step 2: Simplify

From part (a)

The value of the spring constant is,

k=16

06

Part (c) Step 1: Given information

We need to find out the value of natural length

07

Part (c) Step 2: Simplify

From part (a),

The value of natural length is,

x0=4

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