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In Exercises 3.65-3.70, we have provided simple data sets for you to practice the basics of finding measures of variation . For each data set determine.

a) Range

b) sample standard deviation

4,2,0,2,2

Short Answer

Expert verified

a)Range=4b)samplestandarddeviation=1.41

Step by step solution

01

Step 1. Given information. 

We have given data :4,2,0,2,2

02

Step 2. Range of the data.  

Range=Max.value-Min.valueRange=4-0Range=4

03

Step 3. Mean  of the data.    

s={x-x)2n-1Mean,x=xnMean=4+2+0+2+25Mean=1055Mean=2sampiesize,n=5

04

Step 4. Standard deviation of the data.  

Variable x
Deviation from mean x-x
Squared deviation x-x2
42022
20-200
40400

Thus, the standard deviation is

s=x-x2n-1=85-1=2=1.4142

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