Question

Pesticides in Pakistan Pesticides are chemical often used in agriculture to control pests. In Pakistan, 70% of the population depends on agriculture, and pesticide use there has increased rapidly. In the article, "Monitoring Pesticide Residues in Fresh Fruits Marketed in Peshawar, Pakistan" ( American Laboratory, Vol.37, No. 7, pp. 22 to 24) J. Shah et al. sampled the most commonly used fruit in Pakistan and analyzed pesticide residues in the fruit. The amounts, in mg/kg, of the pesticide Dichlorovos for a sample of apples, guavas, and mangos were as follows

Part (a) find$n$

Part (b) Compute$\sum _{}{x}_i$

Part (c) Determine the sample mean. Round your answer to one more decimal place than that used for the observation.

Short answer

Part (a) 12

Part (b) 47.8

Part (c) 3.98

Step-by-step solution

Part (a) Step 1. Given information.

The provided data set is:

0.2, 1.6, 4.0, 5.4, 5.7, 11.4, 0.2, 34, 2.4, 6.6, 4.2, 2.7

Part (a) Step 2. The value of n

The given collection is: 0.2, 1.6, 4.0, 5.4, 5.7, 11.4, 0.2, 34, 2.4, 6.6, 4.2, 2.7

The number of samples is 12

Then

$n=12$

As a result, the value of n is 12.

Part (b) Step 1. Given information.

The provided data set is:

0.2, 1.6, 4.0, 5.4, 5.7, 11.4, 0.2, 34, 2.4, 6.6, 4.2, 2.7

Part (b) Step 2. The value of ∑xi

The value of $\sum _{}{x}_i$is calculated as follows:

$$\begin{gathered} \sum _{}{x}_i=0.2+1.6+4.0+5.4+5.7+11.4+0.2+34+2.4+6.6,+4.2+2.7 \\ \sum _{}{x}_i=47.8 \end{gathered}$$

As a result, the value of $\sum _{}{x}_i$is 47.8

Part (c) Step 1. Given information.

The provided data set is:

0.2, 1.6, 4.0, 5.4, 5.7, 11.4, 0.2, 34, 2.4, 6.6, 4.2, 2.7

Part (c) Step 2 The sample average.

Mean is expressed as follows:

$\overline{x}=\frac{\sum _{}x}{n}$

The mean of the given data set is computed as follows:

role="math" localid="1653158106685" $$\begin{gathered} \overline{x}=\frac{47.8}{12} \\ \overline{x}=3.9833 \end{gathered}$$

As a result, the sample mean days is 3.98.