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What is a confidence interval estimate of a parameter? Why is such an estimate superior to a point estimate?

Short Answer

Expert verified

The interval estimate of the confidence interval is defined as the sample statistic ±margin of error which describe the precision of the estimator and the confidence level gives the uncertainty of the statistics an estimator of the population parameter.

So, confidence intervals is preferred against point estimate for the above two advantages of confidence interval estimate.

Step by step solution

01

:

Suppose we have to infer the unknown value of the population parameter θ( for example population mean).

In the internal estimation of θwe find two limits, say θ1andθ2(θ1<θ2)from the sample observations such that θlies between θ1andθ2with a certain degree of confidence ( measured in terms of probability ) in notation we write,

Pθ1θ2θ3=1-αfor all θwhere αis independent of θand0α1.

The limits θ1andθ2are called confidence limits the interval θ1,θ2is called confidence interval with confidence coefficient 1-αin the words we can say,

The100(1-α)% confidence interval to θbe[θ1,θ2].

02

Step 2

Generally αis taken as very small (close to zero) for instance α=0.01orα=0.05.

This interval θ1,θ2is the interval estimate of unknown population parameters θtogether with the 100(1-α)%confidence level.

In point estimation, we estimate the unknown parameter by a single value. Now instead of the mean of the estimator is equal to ( or close to) an unknown parameter, it may happen that the standard deviation of the estimator is very high i,e. value of the estimators are largely deviated from the population parameter and hence large sampling error may occur.

03

Step 3:

So, it is customary to give, together with the estimate, the standard error ( standard deviation) of the estimator. This idea is actually used in interval estimation we use a confidence interval to express the precision and uncertainty associated with a particular estimator.

The interval estimate of the confidence interval is defined as the sample statistic margin of error which describe the precision of the estimator and the confidence level gives the uncertainty of the statistics an estimator of the population parameter.

So, confidence intervals is preferred against point estimate for the above two advantages of confidence interval estimate.

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Most popular questions from this chapter

The margin of error can be determined if you know only the confidence level, population standard deviation, and sample size.

A confidence interval for a population mean has a length of 162.6.

a. Determine the margin of error.

b. If the sample mean is 643.1, determine the confidence interval.

c. Construct a graph that illustrates your results.

Green Sea Urchins. From the paper "Effects of Chronic Nitrate Exposure on Gonad Growth in Green Sea Urchin Strongylocen. trouts drocbachiensis" (A quaculture, Vol. 242, No. 1-4, pp. 357-363) by SSiikavuopio et al., the weights, xof adult green sea urchins are normally distributed with mean 52.0gand standard deviation 17.2gFor samples of 12such weights, identify the distribution of each of the following variables.

a. x¯-52.017.2/12

b. x^-52.0s/12

M\&Ms. In the article "Sweetening Statistics-What M\&M's Can Teach Us" (Minitab Inc., August 2008), M. Paret and E. Martz discussed several statistical analyses that they performed on bags of M\&Ms. The authors took a random sample of 30 small bags of peanut M\&Ms and obtained the following weights, in grams (g).

a. Determine a 95%lower confidence bound for the mean weight of all small bags of peanut M\&Ms. (Note: The sample mean and sample standard deviation of the data are 52.040gand 2.807grespectively.)

b. Interpret your result in pant (a).

c. According to the package, each small bag of peanut M\&Ms should weigh 49.3gComment on this specification in view of your answer to part (b) It provides equal confidence with a greater lower limit.

Part (c) Because the weight of 49.3g is below the 95% lower confidence bound.

We provide a sample mean, sample size, and population standard deviation. In each case, perform the following tasks.

a. Find a 95% confidence interval for the popularion mean. (Note: You may want to review Example 8.2, which begins on page 316.)

b. Identify and interpret the margin of error:

c. Express the endpoints of the confidence interval in terms of the point estimate and the margin of error.

where, x^=20,n=36,σ=3

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