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Digital Viewing Times. Refer to Exercise 8.130

a. Find and interpret a 90%lower confidence bound for last year's mean time spent per day with digital media by American adults.

b. Compare your one-sided confidence interval in part (a) to the (two-sided) confidence interval found in Exercise 8.130.

Short Answer

Expert verified

Part (a) A 90%lower confidence bound for last year's mean time spent per day by American adults with digital media is 4.477hours.

Part (b)Lowerbound(=4.477)>Lowerlimit(=4.271)

Step by step solution

01

Part (a) Step 1: Given information

n=20, x¯=5.16hrand s=2.30hr

02

Part (a) Step 2: Concept

The formula used: Lower confidence bound =x¯-tαsn

03

Part (a) Step 3: Calculation

Determine a 90%lower confidence bound for American adults' mean daily time spent with digital media last year.

Consider x¯=5.16,n=20, and s=2.30

From "Table IV Values of ta" the required value of ta2for 90%confidence with 19(=20-1)degrees of freedom is 1.328

The lower confidence bound formula is as follows:

Lower confidence bound =x¯-tαsn

x¯-ta2sn=5.16-1.3282.3020=5.16-1.328(0.5143)=5.16-0.683=4.477

As a result, a 90% lower confidence bound for last year's mean time spent per day by American adults with digital media is 4.477 hours.

With 90% confidence, the population mean time spent per day with digital median by American adults is larger than 4.477 hours.

04

Part (b) Step 1: Explanation

Part a: one-sided confidence interval:

Last year's mean time spent per day with digital media by American adults was 4.477hours, according to the 90%lower confidence bound.

Exercise 8.130's two-sided confidence interval:

The (4.271,6.049)confidence interval for the mean time spent per day by American adults with digital media is (4.271,6.049)

The lower confidence bound for the mean time spent per day with digital median by American adults is clearly bigger than the lower confidence limit for the mean time spent per day with digital median by American adults, according to the findings.

That is,Lowerbound(=4.477)>Lowerlimit(=4.271)

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