Question

For a $f-$curve with $df=17$, use Table IV to find cach $t-$value.

a. $t_0$ as

b. I $f_{025}$

C. $t_{0.00s}$

Short answer

Part (a) $t_{0.05}=1.740$

part (b)$t_{0.025}=2.110$

Part (c) $t_{0.005}=2.898$

Step-by-step solution

Part (a) Step 1: Given information

For a $f-$curve with $df=17$

Part (a) Step 2: Calculation

For $d f=17, t_{0.05}=1.740$

Part (b) Step 1: Calculation

For$t_{0.025}=2.110$

Part (c) Step 1: Calculation

For $df=17,t_{0.005}=2.898$