Question

AIDS Cases. According to the Centers for Disease Control and Prevention publication HIV Surveillance Report, the number of AIDS cases in the United States in 2011, by region and race, is as shown in the following contingency table.

Region	White	Black	Other	Total
Northeast	1,100	2,493		5,177
Northwest	1,137		504	3221
South	2,761	7,848		12,867
West		764	1766	4,230
Total			6052	25,435

a. How many cells does this contingency table have?

b. Fill in the missing entries.

c. What was the total number of AIDS cases in the United States in 2011?

d. How many AIDS cases were whites?

e. How many AIDS cases were Southerners?

f. How many AIDS cases were black Westerners?

Short answer

(a) 12 cells

(b)

Region	White	Black	Other	Total
Northeast	1,100	2,493	1,524	5,177
Northwest	1,137	1,580	504	3221
South	2,761	7,848	2,258	12,867
West	1,700	764	1766	4,230
Total	6,698	12,685	6052	25,435

(c)The total number of aids cases in the United states in 2011 is 25,435.

(d) 6698

(e) 12,867

(f) 764

Step-by-step solution

Given 

The given table is

Region	White	Black	Other	Total
Northeast	1,100	2,493		5,177
Northwest	1,137		504	3221
South	2,761	7,848		12,867
West		764	1766	4,230
Total			6052	25,435

Part a. Step 2. Total number of cell

There are 12 cell in contingency table

Part b. Step 3. The missing value 

Region	White	Black	Other	Total
Northeast	1,100	2,493	1,524	5,177
Northwest	1,137	1,580	504	3221
South	2,761	7,848	2,258	12,867
West	1,700	764	1766	4,230
Total	6,698	12,685	6052	25,435

Part c. Step 4. The total no of aids

The total number of aids cases in the United states in 2011 is 25,435.

Part d. Step 5. Finding the number of aids cases were white.

The total number of AIDS cases were whites is

$1,100+1,137+2,761+1,700=6,698$

Part e. Step 6. Finding the number of AIDS cases were Southerners 

The total number of AIDS cases were southerners

$2,761+7,848+2,258=12,867$

Part f. Step 7.  Finding the number of AIDS cases were Westerners

The number of AIDS cases were Westerners

$764$.