Question

Suppose that bivariate data are to be grouped into a contingency table. Determine the number of cells that the contingency table will have if the numbers of possible values for the two variables are

a. two and three.

b. four and three.
c. m and n.

Short answer

The number of cells are :-

(a) $6$

(b) $12$

(c)$mn$

Step-by-step solution

Part (a) Step 1. Given information

The numbers of possible values for the two variables are two and three.

Part (b) Step 2. Number of cells

If the numbers of possible values for the two variables are two and three , then the number of cells are$2\times 3=6$.

Part (b) Step 1. Given information

The numbers of possible values for the two variables are four and three.

Part (b) Step 2. Number of cells

If the numbers of possible values for the two variables are four and three , then the number of cells are$4\times 3=12$.

Part (c) Step 1. Given information

The numbers of possible values for the two variables are m and n.

Part (b) Step 2. Number of cells

If the numbers of possible values for the two variables are m and n , then the number of cells are$m\times n=mn$.