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The chi-square goodness-of-fit test provides a method for performing a hypothesis test about the distribution of a variable that has c possible values. If the number of possible values is 2, that is, c=2, the chi-square goodness-of-fit test is equivalent to a procedure that you studied earlier.

a) Which procedure is that? Explain your answer.

b) Suppose that you want to perform a hypothesis test to decide whether the proportion of a population that has a specified attribute is different from p_0. Discuss the method for performing such a test if you use (1) the one-proportion z-test (page 463) or (2) the chi-square goodness-of-fit test.

Short Answer

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Ans:

(a) The chi-square suitability test provides a hypothesis test method for the distribution of variance with approximately c values. If the probable value of 2 is, i.e., c=2, the chi-square test of goodness-of-fit is equal to the process of one part of z.

(b) Suppose we want to do a hypothesis test to determine if the proportion of people with the specified attribute is different from, p0. We are doing a chi-square goodness-of-fit test.

Step by step solution

01

Step 1. Given information.

given,

The chi-square goodness-of-fit test provides a method for performing a hypothesis test about the distribution of a variable that has c possible values.

02

Step 2. (a)  Which procedure: 

The chi-square suitability test provides a hypothesis test method for the distribution of variance with approximately c values. If the probable value of 2 is, i.e., c=2, the chi-square test of goodness-of-fit is equal to the process of one part of z.

03

Step 3. (b)  Now,

Suppose we want to do a hypothesis test to determine if the proportion of people with the specified attribute is different from,p0. We are doing a chi-square goodness-of-fit test.

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Most popular questions from this chapter

Housing Foundations. The U.S. Census Bureau publishes information about housing units in American Housing Survey for the United States. The following table cross-classifies single-unit occupied housing units by foundation type and tenure of occupier. The frequencies are in thousands.

For single-unit occupied housing units:


OwnerRenterTotal
Full-basement22,9873,30126,288
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a. How many have crawl spaces?

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e. How many are either owner occupied or have a concrete slab?

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Sample size: n=100.

Relative frequencies:0.65,0.30,0.05.

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