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Table 12.4 on page 486 showed the calculated sums of the observed frequencies, the expected frequencies, and their differences. Strictly speaking, those sums are not needed. However, they serve as a check for computational errors.

a) In general, what common value should the sum of the observer frequencies and the sum of the expected frequencies equal? Ex plain your answer.

b) Fill in the blank. The sum of the differences between each observed and expected frequency should equal

c) Suppose that you are conducting a chi-square goodness-of-fit test. If the sum of the expected frequencies does not equal the sample size, what do you conclude?

d) Suppose that you are conducting a chi-square goodness-of-fit test. If the sum of the expected frequencies equals the sample size, can you conclude that you made no error in calculating the expected frequencies? Explain your answer.

Short Answer

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Ans:

(a) The sum of the observed frequencies and the sum of the expected frequencies are equal when it has the common value of "n ".

(b) The sum of the difference between each sight and the expected frequency should be equal to zero.

Description:

If the required amount does not equal zero, there must be an error in the study.

(c) If the number of expected frequencies and the expected number of frequencies do not match the size of the sample, it can be concluded that there is an error in calculating the expected frequencies or in summarizing the expected frequencies and expected frequencies.

(d) There may be an opportunity to make more than two compensation errors in calculating expected frequencies.

Step by step solution

01

Step 1. Give information.

given,

Table 12.4 on page 486 showed the calculated sums of the observed frequencies, the expected frequencies, and their differences.

02

Step 2. (a)  The number of observed frequencies and the expected number of frequencies are equal if we have a standard value such as "n".

Description:

In Table 12.4, it is clear that n=500, the total number of observed frequencies is 500 and the total expected frequency is 500.

The expected amount of frequencies is equal to the sample size provided below:

Ei=npi=npi=n(1)=n

Hence, the sum of the observed frequencies and the sum of the expected frequencies are equal when it has the common value of "n ".

03

Step 3. (b)  Fill in the blanks.

The sum of the difference between each sight and the expected frequency should be equal to zero.

Description:

If the required amount does not equal zero, there must be an error in the study.

04

Step 4. (c)  Explanation:

From subsection (a), it is clear that the amount of observed frequencies and the total expected frequency equals the size of the sample.

If the number of expected frequencies and the expected number of frequencies does not match the size of the sample, it can be concluded that there is an error in calculating the expected frequencies or in summarizing the expected frequencies and expected frequencies.

05

Step 5. (d)  Now,

No, it is not possible to conclude that there is no error in calculating expected frequencies when the total required frequency equals the sample size.

Description:

There may be an opportunity to make more than two compensation errors in calculating expected frequencies.

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Most popular questions from this chapter

In each of Exercises 12.11-12.16, we have given the relative frequencies for the null hypothesis of a chi-square goodness-of-fir text and the sample size. In each case, decide whether Assumptions 1 and 2 for using that text are satisfied.

Sample size : n= 100.

Relative frequencies: 0.44 , 0.25 , 0.30 , 0.01.

In each of the given Exercises, we have given the number of possible values for two variables of a population. For each exercise, determine the maximum number of expected frequencies that can be less than 5 in order that Assumption 2 of Procedure 12.2 on page 506 to be satisfied. Note: The number of cells for a contingency table with m rows and n columns is m⋅n.

12.71 two and three

If the observed and expected frequencies for a chi-square goodness-of-fit test, a chi-square independence test, or a chi-square homogeneity test matched perfectly, what would be the value of the test statistic?

Suppose that you have bivariate data for an entire population.

a. How would you decide whether an association exists between the two variables under consideration?

b. Assuming that you make no calculation mistakes, could your conclusion be in error? Explain your answer.

12.51 Farms. The U.S. Department of Agriculture publishes information about U.S. farms in Census of Agriculture. A joint frequency distribution for number of farms, by acreage and tenure of operator, is provided in the following contingency table. Frequencies are in


Full ownerPart ownerTenantTotal
Under 50
7044
50-17949213038660
180-499198

368
500-999518414149
1000& over4111417172
Total1521541

a. Fill in the six missing entries.

b. How many cells does this contingency table have?

c. How many farms have under 50 acres?

d. How many farms are tenant operated?

e. How many farms are operated by part owners and have between 500 acres and 999 acres, inclusive?

f. How many farms are not full-owner operated?

g. How many tenant-operated farms have 180 acres or more?

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