Question

Suppose that you want to compare the means of three populations by using one-way ANOVA. If the sample sizes are $5$, $6$, and $6$, determine the degrees of freedom for the appropriate F-curve.

Short answer

The degree of freedom is$\mathrm{df}=(2,14)$.

Step-by-step solution

Given Information

Sample sizes of the population are $5$, $6$, and $6$.

The F-degrees freedom of curve are,

$\mathrm{df}=(k-1,n-k)$

where n is the sample size and k is the sample means.

Explanation

The population sample sizes are $5$, $6$. and $6$.

Because the three sample sizes have three sample means,

$k=3$

the F-degrees freedom of curve are,

$$\begin{gathered} \text{df}=(3-1,5+6+6-3) \\ =(2,14) \end{gathered}$$