Question

In Exercises 13–20, express the indicated degree of likelihood as a probability value between 0 and 1.

Sleepwalking Based on a report in Neurology magazine, 29.2% of survey respondents have sleepwalked.

Short answer

The probability that a respondent of the survey has sleepwalked is 0.292.

Step-by-step solution

Given information

In a survey, it was reported that 29.2% of the respondents have sleepwalked.

Define probability

Probability (between 0 and 1) describes the likelihood of an event to occur.

The probability of event A is

$P\left(A\right)=\frac{\text{Number}\text{of}\text{outcomes}\text{in}\text{favour}\text{of}A}{\text{Total}\text{number}\text{of}\text{outcomes}}$

If the number of outcomes is expressed in percentage, then the corresponding probability value can be determined by dividing the percentage value by 100.

Calculate the probability 

The percentage of respondents who have sleepwalked is 29.2%.

The probability of event E(choosing a respondent who has sleepwalked) is

$$\begin{gathered} P\left(E\right)=\frac{29.2}{100} \\ =0.292 \end{gathered}$$

Therefore, the probability of choosing a respondent who has sleepwalked is 0.292.