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Constructing Normal Quantile Plots. In Exercises 17–20, use the given data values to identify the corresponding z scores that are used for a normal quantile plot, then identify the coordinates of each point in the normal quantile plot. Construct the normal quantile plot, and then determine whether the data appear to be from a population with a normal distribution.

Brain Volumes A sample of human brain volumes (cm3) is obtained from those listed in Data Set 8 “IQ and Brain Size” in Appendix B: 1027, 1029, 1034, 1070, 1079, 1079, 963, 1439

Short Answer

Expert verified

The coordinates for the plot are:

Observed

Z-scores

963

-1.53

1027

-0.89

1029

-0.49

1034

-0.16

1070

0.16

1079

0.49

1079

0.89

1439

1.53

The normal quantile plot for given sample is:

The sample of human brain volumes does not appear to be from a population with a normal distribution.

Step by step solution

01

Given information

The sample of human brain volumes in centimeter cube from data set 8 “IQ and Brain size” in Appendix B.

02

Arrange the given data in increasing order

The given sample data arrange in increasing order as:

963, 1027, 1029, 1034, 1070, 1079, 1079, 1439.

In the given data, the sample size is 8. Each value is the proportion of 18of the sample.

So, the cumulative left areas, can be expressed as 12n,32n,52n,andsoon.

For the given sample size,n=8 , the cumulative left areas can be expressed as

116,316,516,716,916,1116,1316and1516

03

Find the Cumulative left areas.

The cumulative left areas expressed in decimal form are 0.0625, 0.1875, 0.3125, 0.4375, 0.5625, 0.6875, 0.8125, and 0.9375.

Refer to the standard normal distribution table, the z-score value corresponding to 0.0625, 0.1875, 0.3125, 0.4375, 0.5625, 0.6875, 0.8125 and 0.9375 for a left-tailed test is equal to -1.53, -0.89, -0.49, -0.16, 0.16, 0.49, 0.89, 1.53.

04

Express the sample values and z-score in (x,y) coordinate .

Pair thesample values of human brain volume with the corresponding z-score in the form of (x, y) as:

(963-1.53), (1027,-0.89),(1029,-0.49), (1034,-0.16), (1070,0.16),

(1079, 0.49), ( 1079, 0.89), and (1439,1.53)

05

Make a Normal Quantile Plot  

Steps to draw a Normal quantile plot are as follows:

  1. Make horizontal axis and vertical axis.
  2. Mark the points 32, 33.3, 34.9 up to 45 on the horizontal axis and points -1.3, -1.04, -0.78, up to 1.3.
  3. Provide title to horizontal and vertical axis as “X values” and “Z-score” respectively.
  4. Mark the co-ordinates and obtain the graph as shown below.

06

Conclude from Normal Quantile Plot

From the normal quantile plot, the points do not show any symmetric pattern. So, the sample of human brain volume does not appear to be from a normally distributed population.

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Most popular questions from this chapter

Finding Bone Density Scores. In Exercises 37–40 assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. In each case, draw a graph, then find the bone density test score corresponding to the given information. Round results to two decimal places.

Find P10, the 10th percentile. This is the bone density score separating the bottom 10% from the top 90%.

Standard Normal Distribution. Find the indicated z score. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1.

Standard normal distribution. In Exercise 17-36, assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1.In each case, Draw a graph, then find the probability of the given bone density test score. If using technology instead of Table A-2, round answers to four decimal places.

Less than -1.23

Significance For bone density scores that are normally distributed with a mean of 0 and a standard deviation of 1, find the percentage of scores that are

a. significantly high (or at least 2 standard deviations above the mean).

b. significantly low (or at least 2 standard deviations below the mean).

c. not significant (or less than 2 standard deviations away from the mean).

In Exercises 5–8, find the area of the shaded region. The graphs depict IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15 (as on the Wechsler IQ test).

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