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For Chapter 2 through Chapter 14, the Cumulative Review Exercises include topics from preceding chapters. For this chapter, we present a few calculator warm-up exercises, with expressions similar to those found throughout this book. Use your calculator to find the indicated values.

Standard Deviation One way to get a very rough approximation of the value of a standard deviation of sample data is to find the range, then divide it by 4. The range is the difference between the highest sample value and the lowest sample value. In using this approach, what value is obtained from the sample data listed in Exercise 1 “Birth Weights”?

Short Answer

Expert verified

For the sample of weights of eight babies (in grams), the approximate value of the sample standard deviation is equal to 575 grams.

Step by step solution

01

Given information

A sample of weights of babies (in grams) is given. The total number of babies is eight. For this sample, the standard deviation is to be computed.

02

Determining the standard deviation

The sample standard deviation can be approximated using therule of range.

Range: Subtracting the minimum value of the dataset from its maximum value gives the range of the dataset.

The rule of range states that thestandard deviationof the data is nearly one-fourth of the range. That is

\({\rm{Standard}}\;{\rm{Deviation}} = \frac{{{\rm{Maximum}}\;{\rm{value}} - {\rm{Minimum}}\;{\rm{value}}}}{4}\)

The range for the given data of weights is equal to 2300 grams, as shown below:

\(\begin{array}{c}{\rm{Range}} = 4000 - 1700\\ = 2300\end{array}\)

The rough estimate of the standard deviation for the weights is calculated as:

\(\begin{array}{c}{\rm{Standard}}\;{\rm{Deviation}} = \frac{{4000 - 1700}}{4}\\ = \frac{{2300}}{4}\\ = 575\end{array}\)

Thus, the rough estimate of the standard deviation for the weights is equal to 575 grams.

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Most popular questions from this chapter

Statistical Significance and Practical Significance. In Exercises 13–16, determine whether the results appear to have statistical significance, and also determine whether the results appear to have practical significance.

Gender Selection In a study of the Gender Aide method of gender selection used to increase the likelihood of a baby being born a girl, 2000 users of the method gave birth to 980 boys and 1020 girls. There is about a 19% chance of getting that many girls if the method had no effect.

In Exercises 21–24, refer to the data in the table below. The entries are white blood cell counts (1000 cells,ML) and red blood cell counts (million cells,ML) from male subjects examined as part of a large health study conducted by the National Center for Health Statistics. The data are matched, so that the first subject has a white blood cell count of 8.7 and a red blood cell count of 4.91, and so on.

Subject


12345
White8.75.97.36.25.9
Red4.915.594.444.85.17

Context Given that the data are matched and considering the units of the data, does it make sense to use the difference between each white blood cell count and the corresponding red blood cell count? Why or why not?

Identify whether the given value is a statistic or a parameter.

Periodic table The average (mean) atomic weight of all elements in the periodic table is 134.355 unified atomic mass units.

Identify whether the given value is a statistic or a parameter.

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