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Using Confidence Intervals

a. Assume that we want to use a 0.05 significance level to test the claim that p1 < p2. Which is better: A hypothesis test or a confidence interval?

b. In general, when dealing with inferences for two population proportions, which two of the following are equivalent: confidence interval method; P-value method; critical value method?

c. If we want to use a 0.05 significance level to test the claim that p1 < p2, what confidence level should we use?

d. If we test the claim in part (c) using the sample data in Exercise 1, we get this confidence interval: -0.000508 < p1 - p2 < - 0.000309. What does this confidence interval suggest about the claim?

Short Answer

Expert verified

a. A hypothesis test is better than a confidence interval.

b. The p-value method and critical value method are equivalent.

c. The 90% confidence interval to test the claim is made about the difference between two population proportion \({p_1}{\rm{ and }}{p_2}\).

d. The given confidence interval suggests that there is sufficient evidence to support the claim that \({p_1} < {p_2}\).

Step by step solution

01

Describe the methods of Inferences about two proportion.

a.The following methods can be used for comparing two population proportion:

1. Hypothesis test

2. Confidence Interval

The hypothesis test is used to test the claims about two population proportions. The confidence interval is used when estimating about the differences between two population proportions.

A hypothesis test is recommended for testing a claim at 0.05 level of significance.

Hence, in this case hypothesis test is better than confidence interval.

02

Check equivalency of three methods

b.In a hypothesis test, there are two methods to test the claims about population proportion,

1. P-value method

2. Critical value method

Both methods are used to test the claim made about two proportions. In p-value method, a probability value is compared to a significance level to make a decision while in critical value method, the test statistic is compared to critical value(s) to make a decision about hypotheses.

The method of confidence interval is used primarily to estimate the difference between two population proportions.

Thus, the P-value method and critical value method are equivalent.

03

State the confidence level

c. As per the table 8-1, for one tailed significance test at 0.05 level of significance, 90% confidence level is recommended.

04

Step 4:Make conclusion about the claim

d. Refer to exercise 1 for the claim stated as,

\(\begin{array}{l}{H_o}:{p_1} = {p_2}\\{H_a}:{p_1} < {p_2}\end{array}\)

Where \({p_1},{p_2}\) are population proportion of children who developed polio after vaccine and in control group respectively.

The given confidence interval is\( - 0.000508 < {p_1} - {p_2} < - 0.000309\).

This confidence does not contain zero. Thus, there is significant difference between two proportion\({{\rm{p}}_{\rm{1}}}{\rm{ and }}{{\rm{p}}_{\rm{2}}}\).

Therefore, the given confidence interval suggests that there is sufficient evidence to support the claim that \({p_1}{\rm{ }}\)is less that \({p_2}\).

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Most popular questions from this chapter

Before/After Treatment Results Captopril is a drug designed to lower systolic blood pressure. When subjects were treated with this drug, their systolic blood pressure readings (in mm Hg) were measured before and after the drug was taken. Results are given in the accompanying table (based on data from โ€œEssential Hypertension: Effect of an Oral Inhibitor of Angiotensin-Converting Enzyme,โ€ by MacGregor et al., British Medical Journal, Vol. 2). Using a 0.01 significance level, is there sufficient evidence to support the claim that captopril is effective in lowering systolic blood pressure?

Subject

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200

174

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191

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Degrees of Freedom

For Example 1 on page 431, we used df smaller of n1-1and n2-1, we got , and the corresponding critical values aret=ยฑ2.201. If we calculate df using Formula 9-1, we getdf=19.063, and the corresponding critical values are t=ยฑ2.201. How is using the critical values of more โ€œconservativeโ€ than using the critical values of ยฑ2.093.

In Exercises 5โ€“20, assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. (Note: Answers in Appendix D include technology answers based on Formula 9-1 along with โ€œTableโ€ answers based on Table A-3 with df equal to the smaller of \({n_1} - 1\) and \({n_2} - 1\).)

Second-Hand Smoke Data Set 12 โ€œPassive and Active Smokeโ€ in Appendix B includes cotinine levels measured in a group of nonsmokers exposed to tobacco smoke (n = 40, \(\bar x\) = 60.58 ng/mL, s = 138.08 ng/mL) and a group of nonsmokers not exposed to tobacco smoke (n = 40, \(\bar x\) = 16.35 ng/mL, s = 62.53 ng/mL). Cotinine is a metabolite of nicotine, meaning that when nicotine is absorbed by the body, cotinine is produced.

a. Use a 0.05 significance level to test the claim that nonsmokers exposed to tobacco smoke have a higher mean cotinine level than nonsmokers not exposed to tobacco smoke.

b. Construct the confidence interval appropriate for the hypothesis test in part (a).

c. What do you conclude about the effects of second-hand smoke?

Testing Claims About Proportions. In Exercises 7โ€“22, test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value or critical value(s), then state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim.

Overlap of Confidence Intervals In the article โ€œOn Judging the Significance of Differences by Examining the Overlap Between Confidence Intervals,โ€ by Schenker and Gentleman (American Statistician, Vol. 55, No. 3), the authors consider sample data in this statement: โ€œIndependent simple random samples, each of size 200, have been drawn, and 112 people in the first sample have the attribute, whereas 88 people in the second sample have the attribute.โ€

a. Use the methods of this section to construct a 95% confidence interval estimate of the difference p1-p2. What does the result suggest about the equality of p1andp2?

b. Use the methods of Section 7-1 to construct individual 95% confidence interval estimates for each of the two population proportions. After comparing the overlap between the two confidence intervals, what do you conclude about the equality ofp1andp2?

c. Use a 0.05 significance level to test the claim that the two population proportions are equal. What do you conclude?

d. Based on the preceding results, what should you conclude about the equality ofp1andp2? Which of the three preceding methods is least effective in testing for the equality ofp1andp2?

Repeat Exercise 12 โ€œIQ and Leadโ€ by assuming that the two population standard deviations are equal, so \({\sigma _1} = {\sigma _2}\). Use the appropriate method from Part 2 of this section. Does pooling the standard deviations yield results showing greater significance?

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