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F Test Statistic

a. If \(s_1^2\)represents the larger of two sample variances, can the F test statistic ever be less than 1?

b. Can the F test statistic ever be a negative number?

c. If testing the claim that \(\sigma _1^2 \ne \sigma _2^2\), what do we know about the two samples if the test statistic F is very close to 1?

d. Is the F distribution symmetric, skewed left, or skewed right?

Short Answer

Expert verified

a.No. If \(s_1^2\)is greater than \(s_2^2\), then the F statistic cannot be less than 1.

b.No. Fstatistic cannot be a negative number.

c.When the value of the F statistic is very close to 1, it means that the two samples have equal variances.

d.The F-distribution is skewed to the right or positively skewed.

Step by step solution

01

Given Information

Let,

\(s_1^2\)denote thelarger of the two sample variances.

\(s_2^2\)denote theSmaller of the two sample variances

\(\sigma _1^2\)denote theLarger variance of the population.

\(\sigma _2^2\)denote the population variance of the other population.

02

Value of the F statistic

a.

The expression of the F statistic is written as follows:

\(F = \frac{{s_1^1}}{{s_2^2}}\)

If\(s_1^2\)is greater than\(s_2^2\), the value of the F statistic is expressed as follows:

\(\begin{array}{c}F = \frac{{s_1^1}}{{s_2^2}}\\ > 1\end{array}\)

Hence, the F test statistic is greater than one when \(s_1^2\)has a larger variance.

No, the F stataistic cannot be less than 1.

03

Range of F - distribution

b.

The F-distribution is the ratio of the squares of the standard deviations of the two samples.

It is known that the square of a number cannot be less than 0.

Hence, the ratio of two positive numbers will also be a positive number.

Therefore, the value of the F statistic can never be negative.

04

Interpreting the value of the F statistic

c.

The following null hypothesis is considered:

Null Hypothesis: The population variances are not equal.

Symbolically,

\({H_0}:\sigma _1^2 \ne \sigma _2^2\)

If the F statistic is close to 1, it implies that the values of the sample variances are approximately equal because the F statistic is the ratio of the two sample variances.

Thus, if the F-statistic is close to 1, the sample variances are approximately equal.

05

Symmetricity of F-distribution

d.

The F-distribution is positively skewed or skewed to the right and not symmetric.

A distribution that is skewed to the right has a tail towards the right side.

Also, the F-distribution has a mean value that is greater than the medina value and hence, the distribution is skewed to the right.

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Most popular questions from this chapter

Are Flights Cheaper When Scheduled Earlier? Listed below are the costs (in dollars) of flights from New York (JFK) to Los Angeles (LAX). Use a 0.01 significance level to test the claim that flights scheduled one day in advance cost more than flights scheduled 30 days in advance. What strategy appears to be effective in saving money when flying?

Delta

Jet Blue

American

Virgin

Alaska

United

1 day in advance

501

634

633

646

633

642

30 days in advance

148

149

156

156

252

313

Determining Sample Size The sample size needed to estimate the difference between two population proportions to within a margin of error E with a confidence level of 1 - a can be found by using the following expression:

E=zα2p1q1n1+p2q2n2

Replace n1andn2 by n in the preceding formula (assuming that both samples have the same size) and replace each of role="math" localid="1649424190272" p1,q1,p2andq2by 0.5 (because their values are not known). Solving for n results in this expression:

n=zα222E2

Use this expression to find the size of each sample if you want to estimate the difference between the proportions of men and women who own smartphones. Assume that you want 95% confidence that your error is no more than 0.03.

In Exercises 5–20, assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. (Note: Answers in Appendix D include technology answers based on Formula 9-1 along with “Table” answers based on Table A-3 with df equal to the smaller of\({n_1} - 1\)and\({n_2} - 1\).)

IQ and Lead Exposure Data Set 7 “IQ and Lead” in Appendix B lists full IQ scores for a random sample of subjects with low lead levels in their blood and another random sample of subjects with high lead levels in their blood. The statistics are summarized below.

a. Use a 0.05 significance level to test the claim that the mean IQ score of people with low blood lead levels is higher than the mean IQ score of people with high blood lead levels.

b. Construct a confidence interval appropriate for the hypothesis test in part (a).

c. Does exposure to lead appear to have an effect on IQ scores?

Low Blood Lead Level: n = 78, \(\bar x\) = 92.88462, s = 15.34451

High Blood Lead Level: n = 21,\(\bar x\)= 86.90476, s = 8.988352

In Exercises 5–20, assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. (Note: Answers in Appendix D include technology answers based on Formula 9-1 along with “Table” answers based on Table A-3 with df equal to the smaller of n1−1 and n2−1.)

Coke and Pepsi Data Set 26 “Cola Weights and Volumes” in Appendix B includes volumes of the contents of cans of regular Coke (n = 36, x = 12.19 oz, s = 0.11 oz) and volumes of the contents of cans of regular Pepsi (n = 36, x = 12.29 oz, s = 0.09 oz).

a. Use a 0.05 significance level to test the claim that cans of regular Coke and regular Pepsi have the same mean volume.

b. Construct the confidence interval appropriate for the hypothesis test in part (a).

c. What do you conclude? Does there appear to be a difference? Is there practical significance?

Degrees of Freedom

For Example 1 on page 431, we used df\( = \)smaller of\({n_1} - 1\)and\({n_2} - 1\), we got\(df = 11\), and the corresponding critical values are\(t = \pm 2.201.\)If we calculate df using Formula 9-1, we get\(df = 19.063\), and the corresponding critical values are\( \pm 2.093\). How is using the critical values of\(t = \pm 2.201\)more “conservative” than using the critical values of\( \pm 2.093\).

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