Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Using Confidence Intervals to Test Hypotheseswhen analyzing the last digits of telephone numbers in Port Jefferson, it is found that among 1000 randomly selected digits, 119 are zeros. If the digits are randomly selected, the proportion of zeros should be 0.1.

a.Use the critical value method with a 0.05 significance level to test the claim that the proportion of zeros equals 0.1.

b.Use the P-value method with a 0.05 significance level to test the claim that the proportion of zeros equals 0.1.

c.Use the sample data to construct a 95% confidence interval estimate of the proportion of zeros. What does the confidence interval suggest about the claim that the proportion of zeros equals 0.1?

d.Compare the results from the critical value method, the P-value method, and the confidence interval method. Do they all lead to the same conclusion?

Short Answer

Expert verified

a. Using the critical value method, it is concluded that there is enough evidence to reject the claim that the population proportion of zeros is equal to 0.1.

b. Using the p-value method, it is concluded that there is enough evidence to reject the claim that the population proportion of zeros is equal to 0.1.

c. Using the confidence interval method, it is concluded that there is not enough evidence to reject the claim that the population proportion of zeros is equal to 0.1.

d. The p-value method and the critical method lead to the same conclusion of rejecting the claim that the population proportion of zeros is equal to 0.1. The confidence interval method leads to the conclusion of failing to reject the claim that the population proportion of zeros is equal to 0.1. All the methods do not lead to the same conclusion.

Step by step solution

01

Given information

In a sample of randomly selected 1000 digits, the number of digits which is zero is equal to 119. It is claimed that the proportion of zeros should be 0.1.

02

State the hypotheses

The hypotheses are as follows:

Null Hypothesis: The proportion of zeros is equal to 0.1.

\({H_0}:p = 0.1\)

Alternative Hypothesis: The proportion of zeros is not equal to 0.1.

\({H_1}:p \ne 0.1\)

03

Sample proportion and population proportions

The sample proportion of zeros is computed below:

\(\begin{array}{c}\hat p = \frac{{119}}{{1000}}\\ = 0.119\end{array}\)

The population proportion of zeros is given below:

\(p = 0.1\)

The population proportion of non-zero numbers is given below:

\(\begin{array}{c}q = 1 - p\\ = 1 - 0.1\\ = 0.9\end{array}\)

04

Compute the test statistic

The test statistic is computed as follows:

\(\begin{array}{c}z = \frac{{\hat p - p}}{{\sqrt {\frac{{pq}}{n}} }}\\ = \frac{{0.119 - 0.1}}{{\sqrt {\frac{{0.1 \times 0.9}}{{1000}}} }}\\ = 2.003\end{array}\)

The test statistic value is 2.003.

05

Critical value method

a.

Referring to the standard normal distribution table, the critical values of z at\(\alpha = 0.05\)for a two-tailed test are -1.96 and 1.96.

The test statistic value does not lie within the two critical values. Thus, the null hypothesis is rejected.

There is enough evidence to reject the claim that the population proportion of zeros is equal to 0.1.

06

P-value method

b.

The two-tailed p-value of z equal to 2.003 is copmputed as follows:

\(\begin{array}{c}2P\left( {z > 2.003} \right) = 2\left( {0.0226} \right)\\ = 0.0452\end{array}\)

Therefore, the p-value of z equal to 2.003 is equal to 0.0452.

Since the p-value is less than 0.05, the null hypothesis is rejected.

There is enough evidence to reject the claim that the population proportion of zeros is equal to 0.1.

07

Confidence interval method

c.

The expression for computing the confidence interval is as follows:

\(\hat p - E < p < \hat p + E\)

The formula to calculate the value of the margin of error (E) is written below:

\(E = {z_{\frac{\alpha }{2}}} \times \sqrt {\frac{{\hat p\hat q}}{n}} \)

The confidence level is 95%. Thus, the corresponding level of significance is equal to 0.05.

The value of\({z_{\frac{\alpha }{2}}}\)when\(\alpha = 0.05\)is equal to 1.96.

The margin of error is computed as shown below:

\(\begin{array}{c}E = {z_{\frac{\alpha }{2}}} \times \sqrt {\frac{{\hat p\hat q}}{n}} \\ = 1.96 \times \sqrt {\frac{{0.119 \times 0.881}}{{1000}}} \\ = 0.0201\end{array}\)

The confidence interval is computed below:

\(\begin{array}{c}\hat p - E < p < \hat p + E\\0.119 - 0.0201 < p < 0.119 + 0.0201\\0.0989 < p < 0.1391\end{array}\)

The 95% confidence interval estimate of the population proportion of zeros is equal to (0.0989, 0.1391).

Since the interval contains the value of 0.1, it can be said that the population proportion of zeros can be equal to 0.1.

Thus, there is not enough evidence to reject the claim that the population proportion of zeros is equal to 0.1.

08

Comparing the results obtained from the 3 methods

d.

The results from the p-value method and the critical method are the same and lead to the conclusion of rejecting the claim that the population proportion of zeros is equal to 0.1.

The result from the confidence method leads to the conclusion of failing to reject the claim that the population proportion of zeros is equal to 0.1.

Thus, all the methods do not lead to the same conclusion.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Identifying H0and H1. In Exercises 5–8, do the following:

a. Express the original claim in symbolic form.

b. Identify the null and alternative hypotheses.

Pulse Rates Claim: The mean pulse rate (in beats per minute, or bpm) of adult males is equal to 69 bpm. For the random sample of 153 adult males in Data Set 1 “Body Data” in Appendix B, the mean pulse rate is 69.6 bpm and the standard deviation is 11.3 bpm.

Finding P-values. In Exercises 5–8, either use technology to find the P-value or use Table A-3 to find a range of values for the P-value.

Airport Data Speeds: The claim that for Verizon data speeds at airports, the mean. The sample size is and the test statistic is

t =-1.625 .

Critical Values. In Exercises 21–24, refer to the information in the given exercise and do the following.

a. Find the critical value(s).

b. Using a significance level of α= 0.05, should we reject H0or should we fail to reject H0?

Exercise 19

Testing Hypotheses. In Exercises 13–24, assume that a simple random sample has been selected and test the given claim. Unless specified by your instructor, use either the P-value method or the critical value method for testing hypotheses. Identify the null and alternative hypotheses, test statistic, P-value (or range of P-values), or critical value(s), and state the final conclusion that addresses the original claim.

How Many English Words? A simple random sample of 10 pages from Merriam-Webster’s Collegiate Dictionary is obtained. The numbers of words defined on those pages are found, with these results: n = 10, x = 53.3 words, s = 15.7 words. Given that this dictionary has 1459 pages with defined words, the claim that there are more than 70,000 defined words is equivalent to the claim that the mean number of words per page is greater than 48.0 words. Assume a normally distributed population. Use a 0.01 significance level to test the claim that the mean number of words per page is greater than 48.0 words. What does the result suggest about the claim that there are more than 70,000 defined words?

Testing Claims About Proportions. In Exercises 9–32, test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, or critical value(s), then state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. Use the P-value method unless your instructor specifies otherwise. Use the normal distribution as an approximation to the binomial distribution, as described in Part 1 of this section.

Cell Phones and Cancer In a study of 420,095 Danish cell phone users, 135 subjects developed cancer of the brain or nervous system (based on data from the Journal of the National Cancer Institute as reported in USA Today). Test the claim of a somewhat common belief that such cancers are affected by cell phone use. That is, test the claim that cell phone users develop cancer of the brain or nervous system at a rate that is different from the rate of 0.0340% for people who do not use cell phones. Because this issue has such great importance, use a 0.005 significance level. Based on these results, should cell phone users be concerned about cancer of the brain or nervous system?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free