Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Testing Claims About Proportions. In Exercises 9–32, test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, or critical value(s), then state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. Use the P-value method unless your instructor specifies otherwise. Use the normal distribution as an approximation to the binomial distribution, as described in Part 1 of this section.

Lie Detectors Trials in an experiment with a polygraph yield 98 results that include 24 cases of wrong results and 74 cases of correct results (based on data from experiments conducted by researchers Charles R. Honts of Boise State University and Gordon H. Barland of the Department of Defense Polygraph Institute). Use a 0.05 significance level to test the claim that such polygraph results are correct less than 80% of the time. Based on the results, should polygraph test results be prohibited as evidence in trials?

Short Answer

Expert verified

Null hypothesis: The proportion of correct results is equal to 80%.

Alternative hypothesis: The proportion of correct results is less than 80%.

Test statistic: -1.111

Critical value: -1.645

P-value: 0.1332

The null hypothesis is failed to reject.

There is not enough evidence to support the claim that the proportion of correct results is less than 80%.

The sample proportion of correct polygraph results equal to 75.5% is not very high, and thus, polygraph test results should be prohibited as evidence in trials as they are not reliable enough.

Step by step solution

01

Given information

Out of 98 polygraph results, 74 are correct results, and 24 are wrong results.

02

Hypotheses

The null hypothesis is written as follows.

The proportion of correct results is equal to 80%.

H0:p=0.80

The alternative hypothesis is written as follows.

The proportion of correct results is less than 80%.

H1:p<0.80

The test is left-tailed.

03

Sample size, sample proportion, and population proportion

The sample size is n=98.

The sample proportion of correct results is computed below.

p^=NumberofcorrectresultsSampleSize=7498=0.755

The population proportion of correct results is equal to 0.80.

04

Test statistic

The value of the test statistic is computed below.

z=p^-ppqn=0.755-0.800.801-0.8098=-1.111

Thus, z=-1.111.

05

Critical value and p-value

Referring to the standard normal table, the critical value of z at α=0.05 for a left-tailed test is equal to -1.645.

Referring to the standard normal table, the p-value for the test statistic value of -1.111 is equal to 0.1332.

As the p-value is greater than 0.05, the null hypothesis is failed to reject.

06

Conclusion of the test

There is not enough evidence to support the claim that the proportion of correct results is less than 80%.

The sample proportion of correct polygraph results equal to 75.5% is not very high. Thus, polygraph results do not appear to have a high accuracy rate that is required to produce them in court.

Thus, their use in the court as evidence should be ceased.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Cans of coke: Confidence interval if we use the data given in exercise 1, we get this 95% confidence interval estimate of the standard deviation of volumes with the new filling process: 0.1846<σ<0.4900 oz. what does this confidence interval tell us about the new filling process?

Type I and Type II Errors. In Exercises 29–32, provide statements that identify the type I error and the type II error that correspond to the given claim. (Although conclusions are usually expressed in verbal form, the answers here can be expressed with statements that include symbolic expressions such as p = 0.1.).

The proportion of people with blue eyes is equal to 0.35.

Lead in Medicine Listed below are the lead concentrations (in ) measured in different Ayurveda medicines. Ayurveda is a traditional medical system commonly used in India. The lead concentrations listed here are from medicines manufactured in the United States (based on data from “Lead, Mercury, and Arsenic in US and Indian Manufactured Ayurvedic Medicines Sold via the Internet,” by Saper et al., Journal of the American Medical Association,Vol. 300, No. 8). Use a 0.05 significance level to test the claim that the mean lead concentration for all such medicines is less than 14 μg/g.

3.0 6.5 6.0 5.5 20.5 7.5 12.0 20.5 11.5 17.5

Testing Claims About Proportions. In Exercises 9–32, test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, or critical value(s), then state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. Use the P-value method unless your instructor specifies otherwise. Use the normal distribution as an approximation to the binomial distribution, as described in Part 1 of this section.

Tennis Instant Replay The Hawk-Eye electronic system is used in tennis for displaying an instant replay that shows whether a ball is in bounds or out of bounds so players can challenge calls made by referees. In a recent U.S. Open, singles players made 879 challenges and 231 of them were successful, with the call overturned. Use a 0.01 significance level to test the claim that fewer than 1/ 3 of the challenges are successful. What do the results suggest about the ability of players to see calls better than referees?

PowerFor a hypothesis test with a specified significance level , the probability of a type I error is, whereas the probability of a type II error depends on the particular value ofpthat is used as an alternative to the null hypothesis.

a.Using an alternative hypothesis ofp< 0.4, using a sample size ofn= 50, and assumingthat the true value ofpis 0.25, find the power of the test. See Exercise 34 “Calculating Power”in Section 8-1. [Hint:Use the valuesp= 0.25 andpq/n= (0.25)(0.75)/50.]

b.Find the value of , the probability of making a type II error.

c.Given the conditions cited in part (a), find the power of the test. What does the power tell us about the effectiveness of the test?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free