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P-Values. In Exercises 17–20, do the following:

a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed.

b. Find the P-value. (See Figure 8-3 on page 364.)

c. Using a significance level of α = 0.05, should we reject H0or should we fail to reject H0?

The test statistic of z = 2.01 is obtained when testing the claim that p0.345.

Short Answer

Expert verified

a. The test is two-tailed.

b. The p-value is equal to 0.0444.

c. The null hypothesis is rejected.

Step by step solution

01

Given Information

A test statistic value of z=2.01 is obtained, and the claim to be tested is p0.345.

02

Identify the hypotheses and tail of the test

a.

In correspondence with the given claim, the following hypotheses are set up:

Null Hypothesis: p=0.345

Alternative Hypothesis: p0.345

Since there is a not equal sign in the alternative hypothesis, the test is two-tailed.

03

P-value

b.

The test statistic to test the given claim is the z-value.

The z-value is equal to 2.01.

Using the standard normal table, the corresponding two-tailed p-value for z-score equal to 2.01 is equal to:

2×Pz<2.01=2×0.0222=0.0444

Thus, the p-value is equal to 0.0444.

To depict the p-value on the normal probability graph, follow the given steps:

  • Plot a horizontal axis representing the z-score. Also, label it as “z-score”.
  • Sketch a bell-shaped curve and draw a vertical dotted line corresponding to the value “0” on the horizontal axis
  • Mark the points “-2.01” and “2.01” on the horizontal axis and then shade the area to the left of the value “-2.01” and to the right of the value “2.01” with blue as shown in the figure.
  • Label the two shaded regions as “p-value = 0.0222”.

The following plot shows the probability value (p-value) as the shaded area under the normal probability graph. Here, the sum of the two p-values corresponds to the requited two-tailed p-value (0.0444).

04

Decision about the test

c.

If the p-value is less than the level of significance, the null hypothesis is rejected; otherwise, not.

Here, the level of significance is equal to 0.05, and the p-value is equal to 0.0444.

Since the p-value is less than 0.05, the null hypothesis is rejected.

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Most popular questions from this chapter

t Test Exercise 2 refers to a t test. What is the t test? Why is the letter t used? What is unrealistic about the z test methods in Part 2 of this section?

In Exercises 1–4, use these results from a USA Today survey in which 510 people chose to respond to this question that was posted on the USA Today website: “Should Americans replace passwords with biometric security (fingerprints, etc)?” Among the respondents, 53% said “yes.” We want to test the claim that more than half of the population believes that passwords should be replaced with biometric security.

Requirements and Conclusions

a. Are any of the three requirements violated? Can the methods of this section be used to test the claim?

b. It was stated that we can easily remember how to interpret P-values with this: “If the P is low, the null must go.” What does this mean?

c. Another memory trick commonly used is this: “If the P is high, the null will fly.” Given that a hypothesis test never results in a conclusion of proving or supporting a null hypothesis, how is this memory trick misleading?

d. Common significance levels are 0.01 and 0.05. Why would it be unwise to use a significance level with a number like 0.0483?

Final Conclusions. In Exercises 25–28, use a significance level of α = 0.05 and use the given information for the following:

a. State a conclusion about the null hypothesis. (Reject H0or fail to reject H0.)

b. Without using technical terms or symbols, state a final conclusion that addresses the original claim.

Original claim: The standard deviation of pulse rates of adult males is more than 11 bpm. The hypothesis test results in a P-value of 0.3045.

Using Technology. In Exercises 5–8, identify the indicated values or interpret the given display. Use the normal distribution as an approximation to the binomial distribution, as described in Part 1 of this section. Use α= 0.05 significance level and answer the following:

a. Is the test two-tailed, left-tailed, or right-tailed?

b. What is the test statistic?

c. What is the P-value?

d. What is the null hypothesis, and what do you conclude about it?

e. What is the final conclusion?

Adverse Reactions to Drug The drug Lipitor (atorvastatin) is used to treat high cholesterol. In a clinical trial of Lipitor, 47 of 863 treated subjects experienced headaches (based on data from Pfizer). The accompanying TI@83/84 Plus calculator display shows results from a test of the claim that fewer than 10% of treated subjects experience headaches.

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