Question

We have given the P-value for a hypothesis test. For each exercise determine the strength of the evidence against null hypothesis.

Given

$P-\mathrm{value}\mathrm{is}0.012$

Short answer

The P-value lies between$0.01<P-\mathrm{value}(0.012)\le 0.05.$

The null hypothesis is clearly rejected as a result of the conditions.

Step-by-step solution

Step 1. Given 

The$P-\mathrm{value}\mathrm{is}0.012.$

Step 2. Conditions for evaluating strength of the evidence 

Criteria for testing the strength of evidence from P values:

weak or no evidence to contradict the null hypothesis.

$-0.05<P-value\le 0.10,$moderate evidence contradict the null hypothesis.

$-0.01<P-value<0.05$, strong evidence contradict the null hypothesis.

$-P-value<0.01,$the strongest evidence contradict the null hypothesis.

Step 3. Conclusion

Here, the$P-valueis0.012,$which lies between 0.01 and 0.05.

That is,$0.01<P-value(0.012)\le 0.05.$

The null hypothesis is clearly rejected as a result of the conditions.