Question

Finding P-values. In Exercises 5–8, either use technology to find the P-value or use Table A-3 to find a range of values for the P-value.

Airport Data Speeds: The claim that for Verizon data speeds at airports, the mean. The sample size is and the test statistic is

t =-1.625 .

Short answer

The p-value lies between 0.10 and 0.20.

Step-by-step solution

Given information

The claim states that the mean of data speeds is $\mu =14.00\text{mbps}$

The sample size is $n=13$with the test statistic $t=-1.625$.

State the hypotheses

As per the claim, the hypotheses are stated as follows.

$$\begin{gathered} H_0:\mu =14(\text{null}\text{hypothesis}) \\ {H}_1:\mu \ne 14(\text{alternative}\text{hypothesis}\text{and}\text{original}\text{claim}) \end{gathered}$$

Hence, it is a two-tailed test.

Compute the degrees of freedom 

The degrees of freedom for the given set of data are as follows.

$$\begin{gathered} df=n-1 \\ =13-1 \\ =12 \end{gathered}$$

Computing p-value using Table A-3

The test is a two-tailed with 12 degrees of freedom and test statistic value of

-1.625.

In Table A-3, check for the value 1.625 in the row with 12 degrees of freedom to see test statistic. The value 1.625 lies between 1.356 and 1.782.

The corresponding two-tailed area indicates the P-value between 0.10 and 0.20.

Hence, this can be written as $0.10<P-value<0.20$

Thus, the range ofp-value is 0.10 and 0.20.